First, determine the head start distance A has. A starts at 1:00 p.m. and B starts at 1:40 p.m., meaning A travels for 40 minutes before B starts.
Convert the time difference to hours: $40 \text{ min} = \frac{40}{60} \text{ h} = \frac{2}{3} \text{ h}$.
A's speed is $40 \text{ km/h}$. The head start distance is calculated as:
Head Start Distance = $Speed_A \times \text{Time Difference} = 40 \text{ km/h} \times \frac{2}{3} \text{ h} = \frac{80}{3} \text{ km}$.
Next, find the relative speed between A and B. Since they are moving in the same direction, the relative speed is the difference between B's speed and A's speed.
Relative Speed = $Speed_B - Speed_A = 50 \text{ km/h} - 40 \text{ km/h} = 10 \text{ km/h}$.
The time B takes to catch up is the head start distance divided by the relative speed.
Catch Up Time = $\frac{\text{Head Start Distance}}{\text{Relative Speed}} = \frac{\frac{80}{3} \text{ km}}{10 \text{ km/h}} = \frac{80}{3 \times 10} \text{ h} = \frac{8}{3} \text{ h}$.
Finally, convert this time into minutes.
Catch Up Time in Minutes = $\frac{8}{3} \text{ h} \times 60 \text{ min/h} = 8 \times 20 \text{ min} = 160 \text{ minutes}$.
B will take 160 minutes to catch up with A.
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