This problem involves calculating the change in distance between two individuals, Raju and Karthik, who are moving at different speeds. Since Karthik is chasing Raju, they are running in the same direction, and we can use the concept of relative speed.
To perform calculations, convert speeds from km/h to meters per minute (m/min).
Since Karthik is chasing Raju (running in the same direction) and Karthik is faster, the relative speed at which Karthik closes the distance is the difference between their speeds.
Relative speed ($v_{rel}$) = Karthik's speed - Raju's speed
$v_{rel} = v_K - v_R$ $v_{rel} = 200 \text{ m/min} - \frac{500}{3} \text{ m/min}$ $v_{rel} = \frac{600 - 500}{3} \text{ m/min} = \frac{100}{3} \text{ m/min}$Calculate the reduction in distance between them after 6 minutes using the relative speed.
Distance closed = Relative speed $\times$ Time
$ \text{Distance closed} = v_{rel} \times t $ $ \text{Distance closed} = \frac{100}{3} \text{ m/min} \times 6 \text{ min} $ $ \text{Distance closed} = 100 \times 2 \text{ m} = 200 \text{ m} $The initial distance is reduced by the distance closed.
Final distance = Initial distance - Distance closed
$ \text{Final distance} = 300 \text{ m} - 200 \text{ m} $ $ \text{Final distance} = 100 \text{ m} $Therefore, the distance between Raju and Karthik after 6 minutes is 100 m.
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Ram traveling at the speed of 3 km/h reaches 15 minutes late. Had he walked at 4 km/h, he would have reached 15 minutes earlier. How much distance does Ram have to cover?