This problem involves calculating the change in distance between two individuals, Raju and Karthik, who are moving at different speeds. Since Karthik is chasing Raju, they are running in the same direction, and we can use the concept of relative speed.
To perform calculations, convert speeds from km/h to meters per minute (m/min).
Since Karthik is chasing Raju (running in the same direction) and Karthik is faster, the relative speed at which Karthik closes the distance is the difference between their speeds.
Relative speed ($v_{rel}$) = Karthik's speed - Raju's speed
$v_{rel} = v_K - v_R$ $v_{rel} = 200 \text{ m/min} - \frac{500}{3} \text{ m/min}$ $v_{rel} = \frac{600 - 500}{3} \text{ m/min} = \frac{100}{3} \text{ m/min}$Calculate the reduction in distance between them after 6 minutes using the relative speed.
Distance closed = Relative speed $\times$ Time
$ \text{Distance closed} = v_{rel} \times t $ $ \text{Distance closed} = \frac{100}{3} \text{ m/min} \times 6 \text{ min} $ $ \text{Distance closed} = 100 \times 2 \text{ m} = 200 \text{ m} $The initial distance is reduced by the distance closed.
Final distance = Initial distance - Distance closed
$ \text{Final distance} = 300 \text{ m} - 200 \text{ m} $ $ \text{Final distance} = 100 \text{ m} $Therefore, the distance between Raju and Karthik after 6 minutes is 100 m.
The driver of a car, which is travelling at a speed of 75 km/h, locates a bus 80 m ahead of him, travelling in the same direction. After 15 seconds, he finds that the bus is 40 m behind the car. What is the speed of the bus (in km/h)?
The distance between two station A and B is 800 km. A train X starts from A and moves towards B at 40 km/h and another trains Y starts from B and moves towards A at 60 km/h. how far from A will they cross each other?
A and B are travelling towards each other from the points P and Q respectively. After crossing each other, A and B take \(6\frac{1}{8}\) hours and 8 hours, respectively, to reach their destinations Q and P, respectively. If the speed of B is 16.8 km/h, then the speed (in km/hr) of A is:
A train leaves station A at 8 am and reaches station B at 12 noon. A car leaves station B at 8:30 am and reaches station A at the same time when the train reaches station B. At what time do they meet?
A and B start moving towards each other from places X and Y respectively, at the same time. The speed of A is 20% more than that of B. After meeting on the way, A and B take \(2\frac{1}{2}\) hours and x hours now to reach Y and X respectively. What is the value of x?