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Question

A carriage driving in a fog passed a man who was walking at the speed of 3 km/h in the same direction. He could see the carriage for 4 min and it was visible to him up to a distance of 100 m. What was the speed of the carriage?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
4.5 km/h

The problem asks for the speed of a carriage given information about its visibility to a man walking in the same direction.

Physics Solution: Carriage Speed Calculation

We need to calculate the speed of the carriage using the concepts of relative speed.

Step 1: Convert Units

Convert the given time and distance into consistent units (kilometers and hours).

  • Time duration ($t$): 4 minutes = $\frac{4}{60}$ hours = $\frac{1}{15}$ hours.
  • Visible distance ($d$): 100 meters = $\frac{100}{1000}$ kilometers = $0.1$ km.
  • Man's speed ($v_m$): $3$ km/h.

Step 2: Determine Relative Speed

The man and the carriage are moving in the same direction. Let the carriage's speed be $v_c$. The relative speed ($v_{rel}$) at which the carriage moves away from the man (or the distance between them increases) is the difference between their speeds:

$v_{rel} = v_c - v_m$

During the 4 minutes, the carriage was visible up to a distance of 100 m. This distance represents the relative distance covered during the observation time.

Step 3: Apply Distance-Speed-Time Formula

Use the formula relating distance, relative speed, and time:

$d = v_{rel} \times t$

Substitute the known values:

$0.1 \text{ km} = v_{rel} \times \frac{1}{15} \text{ h}$

Step 4: Calculate Relative Speed

Solve for $v_{rel}$:

$v_{rel} = 0.1 \text{ km} \times 15 \text{ h}^{-1}$

$v_{rel} = 1.5 \text{ km/h}$

Step 5: Calculate Carriage Speed

Now, find the carriage's speed ($v_c$) using the relative speed formula:

$v_c = v_{rel} + v_m$

$v_c = 1.5 \text{ km/h} + 3 \text{ km/h}$

$v_c = 4.5 \text{ km/h}$

The speed of the carriage is $4.5$ km/h.

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Important Questions from Relative Speed

  1. The driver of a car, which is travelling at a speed of 75 km/h, locates a bus 80 m ahead of him, travelling in the same direction. After 15 seconds, he finds that the bus is 40 m behind the car. What is the speed of the bus (in km/h)?

  2. The distance between two station A and B is 800 km. A train X starts from A and moves towards B at 40 km/h and another trains Y starts from B and moves towards A at 60 km/h. how far from A will they cross each other?

  3. A and B are travelling towards each other from the points P and Q respectively. After crossing each other, A and B take \(6\frac{1}{8}\) hours and 8 hours, respectively, to reach their destinations Q and P, respectively. If the speed of B is 16.8 km/h, then the speed (in km/hr) of A is: 

  4. A train leaves station A at 8 am and reaches station B at 12 noon. A car leaves station B at 8:30 am and reaches station A at the same time when the train reaches station B. At what time do they meet?

  5. A and B start moving towards each other from places X and Y respectively, at the same time. The speed of A is 20% more than that of B. After meeting on the way, A and B take \(2\frac{1}{2}\) hours and x hours now to reach Y and X respectively. What is the value of x?

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