The problem asks for the speed of a carriage given information about its visibility to a man walking in the same direction.
We need to calculate the speed of the carriage using the concepts of relative speed.
Convert the given time and distance into consistent units (kilometers and hours).
The man and the carriage are moving in the same direction. Let the carriage's speed be $v_c$. The relative speed ($v_{rel}$) at which the carriage moves away from the man (or the distance between them increases) is the difference between their speeds:
$v_{rel} = v_c - v_m$
During the 4 minutes, the carriage was visible up to a distance of 100 m. This distance represents the relative distance covered during the observation time.
Use the formula relating distance, relative speed, and time:
$d = v_{rel} \times t$
Substitute the known values:
$0.1 \text{ km} = v_{rel} \times \frac{1}{15} \text{ h}$
Solve for $v_{rel}$:
$v_{rel} = 0.1 \text{ km} \times 15 \text{ h}^{-1}$
$v_{rel} = 1.5 \text{ km/h}$
Now, find the carriage's speed ($v_c$) using the relative speed formula:
$v_c = v_{rel} + v_m$
$v_c = 1.5 \text{ km/h} + 3 \text{ km/h}$
$v_c = 4.5 \text{ km/h}$
The speed of the carriage is $4.5$ km/h.
The driver of a car, which is travelling at a speed of 75 km/h, locates a bus 80 m ahead of him, travelling in the same direction. After 15 seconds, he finds that the bus is 40 m behind the car. What is the speed of the bus (in km/h)?
The distance between two station A and B is 800 km. A train X starts from A and moves towards B at 40 km/h and another trains Y starts from B and moves towards A at 60 km/h. how far from A will they cross each other?
A and B are travelling towards each other from the points P and Q respectively. After crossing each other, A and B take \(6\frac{1}{8}\) hours and 8 hours, respectively, to reach their destinations Q and P, respectively. If the speed of B is 16.8 km/h, then the speed (in km/hr) of A is:
A train leaves station A at 8 am and reaches station B at 12 noon. A car leaves station B at 8:30 am and reaches station A at the same time when the train reaches station B. At what time do they meet?
A and B start moving towards each other from places X and Y respectively, at the same time. The speed of A is 20% more than that of B. After meeting on the way, A and B take \(2\frac{1}{2}\) hours and x hours now to reach Y and X respectively. What is the value of x?