The distance between Delhi and Patna is $480$ km. A train starts from Delhi and travels towards Patna at a speed of $60$ kmph. Another train starts from Patna towards Delhi at a speed of $80$ kmph, but starts $1$ hour after the first train. In how much time, after the first train started, will they meet each other?
$4$ hours
This solution explains how to find the time when two trains traveling towards each other will meet. We are given the total distance between two cities, the speeds of the trains, and the fact that one train starts later than the other. We need to calculate the time elapsed since the first train started.
Let's break down the information provided:
We can solve this problem by considering the head start of the first train.
The first train travels for 1 hour before the second train starts. The distance it covers in this hour is:
Distance = Speed $\times$ Time
$d_{headstart} = S_1 \times 1 \text{ hour} = 60 \text{ kmph} \times 1 \text{ hour} = 60$ km.
When the second train starts its journey, the first train has already covered 60 km. The distance remaining between the two trains is:
$D_{remaining} = \text{Total Distance} - d_{headstart}$
$D_{remaining} = 480 \text{ km} - 60 \text{ km} = 420$ km.
Since the trains are moving towards each other, their speeds add up to determine how quickly they close the distance between them. This is called their relative speed:
$S_{relative} = S_1 + S_2$
$S_{relative} = 60 \text{ kmph} + 80 \text{ kmph} = 140$ kmph.
Now, we can find the time it takes for the trains to cover the remaining distance ($420$ km) at their relative speed ($140$ kmph). Let's call this time $t_{relative}$:
Time = Distance / Speed
$t_{relative} = \frac{D_{remaining}}{S_{relative}} = \frac{420 \text{ km}}{140 \text{ kmph}} = 3$ hours.
This means the trains will meet 3 hours *after* the second train started.
The question asks for the time after the *first* train started. The second train started 1 hour after the first train, and they meet 3 hours after the second train started. Therefore, the total time is:
Total Time $T = (\text{Head start time}) + t_{relative}$
$T = 1 \text{ hour} + 3 \text{ hours} = 4$ hours.
We can also solve this using algebra. Let $t$ be the time in hours since the first train left Delhi.
Setting up the equation:
$60t + 80(t-1) = 480$
Now, solve for $t$:
$60t + 80t - 80 = 480$
$140t = 480 + 80$
$140t = 560$
$t = \frac{560}{140}$
$t = 4$ hours.
Both methods show that the two trains will meet $4$ hours after the first train started its journey from Delhi.
In a circular race of 2500 m, a man and a woman start from a point towards opposite directions with speeds of 37 km/h and 35 km/h, respectively. After how much time from the start of the race will they meet for the first time?
A train of length 600 meters passes another train of length 1000 meters moving in the opposite direction in 96 seconds. If the speed of both the trains is the same, then what is the speed of each train?
Ram traveling at the speed of 3 km/h reaches 15 minutes late. Had he walked at 4 km/h, he would have reached 15 minutes earlier. How much distance does Ram have to cover?
A train, running at a speed of 36 kmph, takes 60 seconds to cross an electric pole. How much time it will take to cross a platform of length 250 meter?