This problem involves calculating the time taken for the dog to catch the cat, considering their speeds and the initial distance between them. This is a classic relative speed problem.
When two objects move in the same direction, the speed at which the faster object gains on the slower object is called the relative speed. It is calculated as the difference between their speeds.
Calculating the relative speed:
$v_{rel} = 24 \text{ km/h} - 10 \text{ km/h} = 14 \text{ km/h}$
The dog needs to cover the initial distance separating it from the cat at this relative speed.
First, ensure the units are consistent. Convert the distance to kilometers:
$d = 280 \text{ m} = \frac{280}{1000} \text{ km} = 0.28 \text{ km}$
Now, use the formula: Time = Distance / Speed
Time ($t$) = $\frac{d}{v_{rel}} = \frac{0.28 \text{ km}}{14 \text{ km/h}}$
$t = 0.02 \text{ hours}$
The options are given in minutes, so convert the calculated time from hours to minutes.
1 hour = 60 minutes
$t \text{ (in minutes)} = 0.02 \text{ hours} \times 60 \text{ minutes/hour}$
$t = 1.2 \text{ minutes}$
Therefore, the dog will take 1.2 minutes to catch the cat.
The driver of a car, which is travelling at a speed of 75 km/h, locates a bus 80 m ahead of him, travelling in the same direction. After 15 seconds, he finds that the bus is 40 m behind the car. What is the speed of the bus (in km/h)?
The distance between two station A and B is 800 km. A train X starts from A and moves towards B at 40 km/h and another trains Y starts from B and moves towards A at 60 km/h. how far from A will they cross each other?
A and B are travelling towards each other from the points P and Q respectively. After crossing each other, A and B take \(6\frac{1}{8}\) hours and 8 hours, respectively, to reach their destinations Q and P, respectively. If the speed of B is 16.8 km/h, then the speed (in km/hr) of A is:
A train leaves station A at 8 am and reaches station B at 12 noon. A car leaves station B at 8:30 am and reaches station A at the same time when the train reaches station B. At what time do they meet?
A and B start moving towards each other from places X and Y respectively, at the same time. The speed of A is 20% more than that of B. After meeting on the way, A and B take \(2\frac{1}{2}\) hours and x hours now to reach Y and X respectively. What is the value of x?