This problem requires calculating the time it takes for two trains, moving in opposite directions, to completely pass each other after they meet.
Determine the total distance needed for the trains to clear each other. This is the sum of their lengths:
Total Length ($L$) = $L_1 + L_2$
$L = 136 \text{ m} + 185 \text{ m} = 321 \text{ m}$
Calculate the relative speed ($S_{rel}$) of the two trains. Since they are moving in opposite directions, their speeds add up:
$S_{rel} = S_1 + S_2$
$S_{rel} = 70 \text{ km/h} + 65 \text{ km/h} = 135 \text{ km/h}$
Convert the relative speed from kilometers per hour (km/h) to meters per second (m/s) for consistency with the length unit:
$S_{rel} (\text{m/s}) = S_{rel} (\text{km/h}) \times \frac{5}{18}$
$S_{rel} = 135 \times \frac{5}{18} = 37.5 \text{ m/s}$
Calculate the time ($t$) required for the trains to clear each other using the formula: Time = Total Distance / Relative Speed:
$t = \frac{L}{S_{rel}}$
$t = \frac{321 \text{ m}}{37.5 \text{ m/s}}$
$t = 8.56 \text{ s}$
The time required for the two trains to completely clear each other is 8.56 seconds.
Eight railway stations A, B, C, D, E, F, G and H are connected either by two-way passages or one-way passages. One-way passages are from C to A, E to G, B to F, D to H, G to C, E to C and H to G. Two-way passages are between A and E, G and B, F and D, and E and D.
If the route between G and C is closed, which one of the following stations need not be passed through while travelling from H to C?
A daily train is to be introduced between station A and station B starting from each end at 6 AM and the journey is to be completed in 42 hours. What is the number of trains needed in order to maintain the Shuttle Service?
A train with a uniform speed passes a 122 meters long platform in 17 seconds and a 210 meters long bridge in 25 seconds. The speed of the train is:
How long does a train 153 meters long running at the rate of 90 kmph take to cross a bridge 622 meters in length?
A train passes a 360 metre long platform in 40 seconds and a man standing on the platform in 16 seconds. The speed of the train is: