To solve problems involving a train crossing a platform, the total distance the train must cover includes both its own length and the length of the platform.
First, calculate the total distance the train needs to travel to completely cross the platform.
Train Length = 450 m
Platform Length = 150 m
Total Distance = Train Length + Platform Length
Total Distance = 450 m + 150 m = 600 m
The train's speed is given in kilometers per hour (km/h), but the distances are in meters (m). Convert the speed to meters per second (m/s) for consistency.
Speed = 80 km/h
To convert km/h to m/s, multiply by \frac{5}{18}.
Speed = 80 $\times$ \frac{5}{18} = \frac{400}{18} = \frac{200}{9} m/s
Now, use the formula Time = Distance / Speed to find the time taken.
Time = \frac{\text{Total Distance}}{\text{Speed}}
Time = \frac{600 \text{ m}}{\frac{200}{9} \text{ m/s}}
Time = 600 $\times$ \frac{9}{200}
Time = 3 $\times$ 9 = 27 s
Therefore, the time taken by the train to cross the platform is 27 seconds.
A train is to cover 370 km at a uniform speed. After running 100 km, the train could run at a speed 5 km/h less than its normal speed due to some technical fault. The train got delayed by 36 minutes. What is the normal speed of the train, in km/h?
A train travelling at 36 km/h crosses a pole in 25 seconds. How much time (in seconds) will it take to cross a bridge 250 m long?
A train covers 450 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less to cover the same distance. How much time will it take to cover 315 km at its usual speed?
A train crosses a pole in 12 sec, and a bridge of length 170 m in 36 sec. Then the speed of the train is:
The ratio of the speeds of two trains is 2 : 7. If the first train runs 250 km in 5 hours, then the sum of the speeds (in km/h) of both the trains is: