We need to find the length of the train ($L$) given two scenarios:
Let the speed of the train be $S$ m/s.
Scenario 1: Crossing a man
When a train crosses a man, the distance covered is equal to the length of the train ($L$).
Time = Distance / Speed
$10 = L / S$
From this, we get the relation: $L = 10S$ (Equation 1)
Scenario 2: Crossing a platform
When a train crosses a platform, the total distance covered is the length of the train ($L$) plus the length of the platform (260 m).
Time = Total Distance / Speed
$20 = (L + 260) / S$
This gives us: $20S = L + 260$ (Equation 2)
Solving for Length ($L$)
Substitute the value of $L$ from Equation 1 into Equation 2:
$20S = (10S) + 260$
Subtract $10S$ from both sides:
$20S - 10S = 260$
$10S = 260$
Calculate the speed $S$:
$S = 260 / 10$
$S = 26$ m/s
Now, substitute the speed $S$ back into Equation 1 to find the length $L$:
$L = 10S$
$L = 10 \times 26$
$L = 260$ m
The length of the train is 260 meters.
Eight railway stations A, B, C, D, E, F, G and H are connected either by two-way passages or one-way passages. One-way passages are from C to A, E to G, B to F, D to H, G to C, E to C and H to G. Two-way passages are between A and E, G and B, F and D, and E and D.
If the route between G and C is closed, which one of the following stations need not be passed through while travelling from H to C?
A daily train is to be introduced between station A and station B starting from each end at 6 AM and the journey is to be completed in 42 hours. What is the number of trains needed in order to maintain the Shuttle Service?
A train with a uniform speed passes a 122 meters long platform in 17 seconds and a 210 meters long bridge in 25 seconds. The speed of the train is:
A train passes a 360 metre long platform in 40 seconds and a man standing on the platform in 16 seconds. The speed of the train is:
The length of a train and that of a platform are equal. If with a speed of 108 km/hr the train crosses the platform in one minute. Then the length of the train (in metres) is: