This problem involves calculating the time taken for a train of a specific length, moving at a constant speed, to pass a fixed point (a post). When a train passes a post, the distance it covers is equal to its own length.
We need to find the time it takes for the train to cover its own length at the given speed.
Since the distance is in meters, we must convert the speed from km/h to m/s for consistency. The conversion factor is $\frac{5}{18}$.
Speed in m/s = $90 \times \frac{5}{18}$
Speed = $5 \times 5 = 25$ m/s
The formula relating time, distance, and speed is: Time = $\frac{\text{Distance}}{\text{Speed}}$
Time = $\frac{180 \text{ m}}{25 \text{ m/s}}$
Time = $7.2$ s
Therefore, it will take the train 7.2 seconds to pass the post.
A train is to cover 370 km at a uniform speed. After running 100 km, the train could run at a speed 5 km/h less than its normal speed due to some technical fault. The train got delayed by 36 minutes. What is the normal speed of the train, in km/h?
A train travelling at 36 km/h crosses a pole in 25 seconds. How much time (in seconds) will it take to cross a bridge 250 m long?
A train covers 450 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less to cover the same distance. How much time will it take to cover 315 km at its usual speed?
A train crosses a pole in 12 sec, and a bridge of length 170 m in 36 sec. Then the speed of the train is:
The ratio of the speeds of two trains is 2 : 7. If the first train runs 250 km in 5 hours, then the sum of the speeds (in km/h) of both the trains is: