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Question

The value of the expression (1.552 + 0.552 + 1.55 × 0.55) is equal to:

This question was previously asked in
SSC CGL 2024 (Tier-I) Previous Year Paper (17-Sep-2024) (Shift 3)
The correct answer is

1.553 − 0.553

Step 1: Identify the Algebraic Pattern
 

Let a = 1.55
Let b = 0.55

By substituting these variables, the expression becomes:

a2 + b2 + ab

Step 2: Recall the Relevant Algebraic Identity
The pattern a2 + ab + b2 is a key component of the "difference of cubes" identity. The full identity is:

a3 − b3 = (a − b)(a2 + ab + b2)

Step 3: Apply the Identity to the Expression
From the identity, we can see that our expression `(a² + ab + b²)` can be isolated by dividing both sides by `(a - b)`:

(a2 + ab + b2) = (a3 − b3) / (a − b)

To proceed, we must calculate the value of `(a - b)`.

Step 4: Calculate the Value of (a − b)
Using the values we assigned in Step 1:

a − b = 1.55 − 0.55 = 1

Step 5: Arrive at the Final Solution
Now, substitute the result from Step 4 back into the equation from Step 3:

(a2 + ab + b2) = (a3 − b3) / 1

This simplifies to:

a2 + ab + b2 = a3 − b3


Conclusion

By substituting the original numbers back into the simplified equation, we have proven that the initial expression is indeed equal to the difference of their cubes:

1.552 + 0.552 + (1.55 × 0.55) = 1.553 − 0.553

 

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Important Questions from Linear Equation in 2 or more Variables

  1. If \(3x+6y+9z = \dfrac{20}{3}, 6x+9y + 3z = \dfrac{17}{3}\)  and  \(18x+ 27y - z = \dfrac{113}{9}\) , then what is the value of  \(75x+113y \ ?\)

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