The sum of two numbers is 40 and their difference is 4. What is the product of the numbers?
396
Let the two numbers be \(x\) and \(y\) with \(x>y\). We are given \(x+y=40\) and \(x-y=4\).
Add the two equations: \((x+y)+(x-y)=40+4\), so \(2x=44\) and \(x=22\).
Subtract to find the other number: \(y=40-22=18\).
The product is \(22 \times 18 = 396\).
Hence, the product of the numbers is 396.
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