The value of 90 ÷ 20 of 6 × [11 ÷ 4 of {3 × 2 - (3 - 8)}] ÷ (9 ÷ 3 × 2) is:
The problem asks us to find the value of a given mathematical expression involving several operations like division, multiplication, 'of', and different types of brackets (parentheses, curly braces, and square brackets). To solve this correctly, we must follow the order of operations, often remembered using acronyms like BODMAS or PEMDAS.
The BODMAS rule dictates the sequence in which operations should be performed:
Let's break down the given expression: \(90 \div 20 \text{ of } 6 \times [11 \div 4 \text{ of } \{3 \times 2 - (3 - 8)\}] \div (9 \div 3 \times 2)\).
First, calculate the expression inside the parentheses: \( (3 - 8) \).
\( (3 - 8) = -5 \)
The expression inside the curly braces becomes \( \{3 \times 2 - (-5)\} \).
Next, solve the expression inside the curly braces: \( \{3 \times 2 - (-5)\} \).
The expression inside the square brackets becomes \( [11 \div 4 \text{ of } \{11\}] \), which simplifies to \( [11 \div 4 \text{ of } 11] \).
Next, calculate '4 of 11' inside the square brackets. 'Of' means multiplication and is done before division/multiplication outside brackets.
\( 4 \text{ of } 11 = 4 \times 11 = 44 \)
The expression inside the square brackets becomes \( [11 \div 44] \).
Now, perform the division inside the square brackets:
\( [11 \div 44] = [\frac{11}{44}] = [\frac{1}{4}] \)
Look at the last part of the main expression: \( (9 \div 3 \times 2) \). This is treated as a single unit divided by the rest of the expression.
So, \( (9 \div 3 \times 2) = 6 \).
Now, look at the first part of the main expression: \( 90 \div 20 \text{ of } 6 \). Calculate '20 of 6'.
\( 20 \text{ of } 6 = 20 \times 6 = 120 \)
The main expression is now simplified to: \( 90 \div 120 \times [\frac{1}{4}] \div 6 \).
Finally, solve the remaining divisions and multiplications from left to right.
Simplify the fraction \( \frac{3}{96} \) by dividing the numerator and the denominator by their greatest common divisor, which is 3.
\( \frac{3 \div 3}{96 \div 3} = \frac{1}{32} \)
The value of the expression is \( \frac{1}{32} \).
| Step | Part of Expression Solved | Calculation | Result |
|---|---|---|---|
| 1 | \( (3 - 8) \) | \( 3 - 8 \) | \( -5 \) |
| 2 | \( \{3 \times 2 - (-5)\} \) | \( 6 - (-5) \) | \( 11 \) |
| 3 | \( 4 \text{ of } 11 \) | \( 4 \times 11 \) | \( 44 \) |
| 4 | \( [11 \div 44] \) | \( \frac{11}{44} \) | \( \frac{1}{4} \) |
| 5 | \( (9 \div 3 \times 2) \) | \( (3 \times 2) \) | \( 6 \) |
| 6 | \( 20 \text{ of } 6 \) | \( 20 \times 6 \) | \( 120 \) |
| 7 | \( 90 \div 120 \times \frac{1}{4} \div 6 \) | \( \frac{90}{120} \times \frac{1}{4} \times \frac{1}{6} \) | \( \frac{3}{4} \times \frac{1}{4} \times \frac{1}{6} = \frac{3}{96} \) |
| 8 | Simplify \( \frac{3}{96} \) | \( \frac{3 \div 3}{96 \div 3} \) | \( \frac{1}{32} \) |
Understanding the order of operations is crucial for correctly evaluating mathematical expressions. Without a standard order, the same expression could yield different results. BODMAS (or PEMDAS) provides this standard. Remember that division and multiplication have the same priority and should be performed from left to right as they appear in the expression. Similarly, addition and subtraction have the same priority and are performed from left to right.
The term 'of' is often used in problems involving fractions or percentages (e.g., 'half of 10', '20% of 50'). In the context of BODMAS, 'of' signifies multiplication but is typically evaluated before any other multiplication or division operations present in the same level of the expression (after brackets and orders/exponents).
The value of 1800 ÷ 20 × {(12 - 6) + (24 - 12)} is:
The value of 20 ÷ 5 of 8 × [9 ÷ 6 × (6 - 3)] - (10 ÷ 2 of 20) is:
The value of \(\left( {18 \div 2\;of\frac{1}{4}} \right)\; \times \;\left( {\frac{2}{3} \div \frac{3}{4}\; \times \;\frac{5}{8}} \right) \div \left( {\frac{2}{3} \div \frac{3}{4}of\frac{3}{4}} \right)\) is:
The value of 18 ÷ [26 - {25 - (15 - 5) ÷ 2}] of 12 + 2 - 2 ÷ 4 × 16 is:
Simplify the following expression:
8 ÷ 4 of 2 - 15 ÷ 2 of 5 - 6 ÷ 5 × (-7 + 5) of 2