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Question

The value of 3 ÷ 18 of 3 × 6 - 22 × 6 ÷ 18 - 3 ÷ 2 + 10 - 3 ÷ 9 of 3 × 9 is

This question was previously asked in
SSC CGL 2020 Tier-II (English) Previous Year Paper (29-Jan-2022)
The correct answer is

1/2

Evaluating the Expression using BODMAS

The given expression is:

\(3 \div 18 \text{ of } 3 \times 6 - 22 \times 6 \div 18 - 3 \div 2 + 10 - 3 \div 9 \text{ of } 3 \times 9\)

Apply BODMAS. 'Of' is evaluated before division/multiplication.

  • \(18 \text{ of } 3 = 54\)
  • \(9 \text{ of } 3 = 27\)

Expression becomes:

\(3 \div 54 \times 6 - 22 \times 6 \div 18 - 3 \div 2 + 10 - 3 \div 27 \times 9\)

Evaluate division and multiplication from left to right:

  • \(3 \div 54 \times 6 = \frac{1}{18} \times 6 = \frac{1}{3}\)
  • \(22 \times 6 \div 18 = 132 \div 18 = \frac{22}{3}\)
  • \(3 \div 2 = \frac{3}{2}\)
  • \(3 \div 27 \times 9 = \frac{1}{9} \times 9 = 1\)

Expression reduces to:

\(\frac{1}{3} - \frac{22}{3} - \frac{3}{2} + 10 - 1\)

Now perform addition/subtraction from left to right:

  • \(\frac{1}{3} - \frac{22}{3} = \frac{-21}{3} = -7\)
  • \(-7 - \frac{3}{2} = \frac{-17}{2}\)
  • \(\frac{-17}{2} + 10 = \frac{3}{2}\)
  • \(\frac{3}{2} - 1 = \frac{1}{2}\)

Hence the value of the expression is \(\frac{1}{2}\).

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