All Exams Test series for 1 year @ ₹349 only
Question

The value of 3 ÷ 18 of 3 × 6 - 22 × 6 ÷ 18 - 3 ÷ 2 + 10 - 3 ÷ 9 of 3 × 9 is

This question was previously asked in
SSC CGL 2020 Tier-II (English) Previous Year Paper (29-Jan-2022)
The correct answer is

1/2

Evaluating the Expression using BODMAS

The given expression is:

\(3 \div 18 \text{ of } 3 \times 6 - 22 \times 6 \div 18 - 3 \div 2 + 10 - 3 \div 9 \text{ of } 3 \times 9\)

Apply BODMAS. 'Of' is evaluated before division/multiplication.

  • \(18 \text{ of } 3 = 54\)
  • \(9 \text{ of } 3 = 27\)

Expression becomes:

\(3 \div 54 \times 6 - 22 \times 6 \div 18 - 3 \div 2 + 10 - 3 \div 27 \times 9\)

Evaluate division and multiplication from left to right:

  • \(3 \div 54 \times 6 = \frac{1}{18} \times 6 = \frac{1}{3}\)
  • \(22 \times 6 \div 18 = 132 \div 18 = \frac{22}{3}\)
  • \(3 \div 2 = \frac{3}{2}\)
  • \(3 \div 27 \times 9 = \frac{1}{9} \times 9 = 1\)

Expression reduces to:

\(\frac{1}{3} - \frac{22}{3} - \frac{3}{2} + 10 - 1\)

Now perform addition/subtraction from left to right:

  • \(\frac{1}{3} - \frac{22}{3} = \frac{-21}{3} = -7\)
  • \(-7 - \frac{3}{2} = \frac{-17}{2}\)
  • \(\frac{-17}{2} + 10 = \frac{3}{2}\)
  • \(\frac{3}{2} - 1 = \frac{1}{2}\)

Hence the value of the expression is \(\frac{1}{2}\).

Was this answer helpful?

Similar Questions

  1. The value of 1800 ÷ 20 × {(12 - 6) + (24 - 12)} is:

  2. Find the value of k if 13 - [10 - {16 + 8 ÷ (k - 2)} + 2] = 20.

  3. The value of 40 ÷ 5 of 2 × [18 ÷ 6 × (12 − 9) of 5 − (3 − 8)] ÷ 25 is:

  4. The value of 90 ÷ 20 of 6 × [11 ÷ 4 of {3 × 2 - (3 - 8)}] ÷ (9 ÷ 3 × 2) is:

  5. If ‘A’ stands for ‘subtraction’, ‘B’ stands for ‘multiplication’, ‘C’ stands for ‘addition’ and ‘D’ stands for ‘division’, then what is the value of the following expression?

    32 B 4 A 12 B (35 A 24) C 52 D 4
  6. What is the value of 9991 × 10009?

  7. The value of 3.8 – (4.2 ÷ 0.7 × 3) + 5 × 2 ÷ 0.5 is∶

  8. Simplify the following expression:

    7 × 4 ÷ 21 of 4 - 5 ÷ 4 × (9 - 13) + 2 - 2 ÷ 8

  9. The value of 15.2 + 5.8 ÷ 2.9 × 2 - 3.5 × 2 ÷ 0.5 is equal to:

  10. The value of (5 + 3 ÷ 5 × 5) ÷ (3 ÷ 3 of 6) of (4 × 4 ÷ 4 of 4 + 4 ÷ 4 × 4) is:


Important Questions from Bodmas Rule

  1. If 2945 ÷ 19 – 11 × 5 = 29 + a, find the value of a.

  2. DIRECTIONS: What should come in place of the question mark (?) in the following question?

    3800 - 22 × 1968 ÷ 48 = ? × 7

  3. Solve: {7.88 × 2 + 2.4 × 5 - 242.4 ÷ 4 + [9.2 × 4 - 2.46 of 3 + (36.3 ÷ 3 - 1.42 × 2)]} 

  4. What will come in the place of question mark (?) in the given expression?

    (420 ÷ 12 × 35 + 452- 152) = ?2

  5. Evaluate: (13 × 8 - √81 × 6 + 1 ) ÷ (√49 + 72 - 18 × 2 + 19)

Need Expert Advice?
Upcoming Exams
UPSSSC PET
October 25, 2026
SSC JE
November 02, 2026
SSC CPO
November 20, 2026
SSC CHSL
November 30, 2026
Test Series
SSC CGL img
SSC
SSC CGL (Tier I + Tier II) 2026 Mock Test Series - Latest Pattern
2503 Tests 6 Tests Free
7972 Attempts
4.2(909)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App