If 2945 ÷ 19 – 11 × 5 = 29 + a, find the value of a.
71
The problem asks us to find the value of 'a' in the given mathematical equation: \( 2945 \div 19 - 11 \times 5 = 29 + a \). To solve this, we need to follow the order of operations, often remembered by acronyms like BODMAS or PEMDAS.
BODMAS stands for:
We will apply this order to the left side of the equation first.
The equation is \( 2945 \div 19 - 11 \times 5 = 29 + a \).
According to BODMAS, we perform division and multiplication before subtraction and addition. We work from left to right for these operations.
First, calculate the division:
\( 2945 \div 19 \)
Let's perform the division:
\( \begin{array}{r} 155 \\ 19\overline{)2945} \\ -\underline{19}\downarrow\phantom{00} \\ 104\downarrow\phantom{0} \\ -\underline{95}\downarrow\phantom{0} \\ 95 \\ -\underline{95} \\ 0 \end{array} \)
So, \( 2945 \div 19 = 155 \).
Next, calculate the multiplication:
\( 11 \times 5 = 55 \)
Now the equation becomes:
\( 155 - 55 = 29 + a \)
Calculate the left side of the equation:
\( 155 - 55 = 100 \)
The equation is now:
\( 100 = 29 + a \)
To find the value of 'a', we need to isolate it on one side of the equation. We can do this by subtracting 29 from both sides of the equation:
\( 100 - 29 = 29 + a - 29 \)
\( 100 - 29 = a \)
\( 71 = a \)
So, the value of 'a' is 71.
We can verify the answer by substituting \( a = 71 \) back into the original equation:
Left side: \( 2945 \div 19 - 11 \times 5 = 155 - 55 = 100 \)
Right side: \( 29 + a = 29 + 71 = 100 \)
Since the left side equals the right side, our calculated value for 'a' is correct.
The value of a is 71.
| Concept | Description | Relevance to Problem |
|---|---|---|
| Order of Operations (BODMAS/PEMDAS) | Rules defining the sequence for evaluating mathematical expressions: Brackets, Orders, Division/Multiplication, Addition/Subtraction. | Essential for correctly evaluating the left side of the equation \(2945 \div 19 - 11 \times 5\). |
| Solving Linear Equations | Finding the value(s) of the unknown variable(s) that satisfy the equation. | Used to isolate and find the value of 'a' in the equation \(100 = 29 + a\). |
| Basic Arithmetic Operations | Addition, Subtraction, Multiplication, Division. | Fundamental operations used throughout the problem solving process. |
An equation is a mathematical statement that shows two expressions are equal. The process of solving an equation involves manipulating it to find the value of the unknown variable that makes the statement true.
For a simple linear equation like \( 100 = 29 + a \), the goal is to get the variable 'a' by itself on one side. We do this by performing the inverse operation to what is being done to 'a'. In this case, 29 is being added to 'a'. The inverse operation of addition is subtraction. So, we subtract 29 from both sides to maintain the equality:
\( 100 - 29 = 29 + a - 29 \)
\( 71 = a \)
This principle applies to multiplication (inverse is division) and division (inverse is multiplication) as well when isolating a variable. Always perform the same operation on both sides of the equals sign to keep the equation balanced.
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