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Question

The sum of the present ages of a father and his son is 60 years. 5 years from now, the ratio of their ages will be 5 : 2. What is the current age of the son?

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is

15 years

This problem involves finding the present age of a son given information about the sum of his and his father's present ages and the ratio of their ages after a certain number of years.

Understanding the Father and Son Age Problem

We are given two main pieces of information:

  1. The sum of the present ages of the father and the son is 60 years.
  2. 5 years from now, the ratio of their ages will be 5 : 2.

Our goal is to determine the son's current age.

Setting Up Equations for Ages

Let's use variables to represent their current ages:

  • Let \(F\) be the present age of the father.
  • Let \(S\) be the present age of the son.

From the first piece of information, we can write the equation:

\(\qquad F + S = 60 \quad (Equation\ 1)\)

Now, let's consider their ages 5 years from now:

  • Father's age 5 years from now will be \(F + 5\).
  • Son's age 5 years from now will be \(S + 5\).

The second piece of information tells us the ratio of these future ages is 5 : 2. We can write this as:

\(\qquad \frac{F + 5}{S + 5} = \frac{5}{2} \quad (Equation\ 2)\)

Solving the System of Equations

We now have a system of two linear equations with two variables (\(F\) and \(S\)). We can solve this system to find the values of \(F\) and \(S\).

From Equation 1, we can express \(F\) in terms of \(S\):

\(\qquad F = 60 - S\)

Now, substitute this expression for \(F\) into Equation 2:

\(\qquad \frac{(60 - S) + 5}{S + 5} = \frac{5}{2}\)

Simplify the numerator:

\(\qquad \frac{65 - S}{S + 5} = \frac{5}{2}\)

To solve for \(S\), we can cross-multiply:

\(\qquad 2 \times (65 - S) = 5 \times (S + 5)\)

Distribute the numbers on both sides:

\(\qquad 130 - 2S = 5S + 25\)

Now, we need to gather the \(S\) terms on one side and the constant terms on the other side. Add \(2S\) to both sides:

\(\qquad 130 = 5S + 2S + 25\)

\(\qquad 130 = 7S + 25\)

Subtract 25 from both sides:

\(\qquad 130 - 25 = 7S\)

\(\qquad 105 = 7S\)

Finally, divide by 7 to find the value of \(S\):

\(\qquad S = \frac{105}{7}\)

\(\qquad S = 15\)

The Son's Current Age

The value we found for \(S\) is 15. Since \(S\) represents the present age of the son, the son's current age is 15 years.

Verification

Let's check if this answer fits the original conditions:

  • If the son's current age is 15, and the sum of their ages is 60, then the father's current age is \(F = 60 - 15 = 45\) years.
  • 5 years from now, the son's age will be \(15 + 5 = 20\) years.
  • 5 years from now, the father's age will be \(45 + 5 = 50\) years.
  • The ratio of their ages 5 years from now is \(\frac{50}{20} = \frac{5}{2}\), which matches the ratio given in the problem.

The calculated age satisfies both conditions, confirming that the son's current age is 15 years.

Person Present Age Age 5 Years From Now
Father \(F = 45\) \(F+5 = 50\)
Son \(S = 15\) \(S+5 = 20\)
Conditions Check: \(F+S = 45+15=60\) (Correct) Ratio \(\frac{F+5}{S+5} = \frac{50}{20} = \frac{5}{2}\) (Correct)

Revision Table: Key Concepts

Concept Explanation Application in Problem
Forming Linear Equations Translating word problems into algebraic equations using variables. \(F+S=60\) and \(\frac{F+5}{S+5} = \frac{5}{2}\)
Solving System of Equations Finding the values of variables that satisfy all equations in the system, often using substitution or elimination. Using \(F=60-S\) in the second equation to solve for \(S\).
Ratio and Proportion Expressing the relationship between two quantities as a fraction and using cross-multiplication to solve equations involving ratios. Setting up \(\frac{F+5}{S+5} = \frac{5}{2}\) and solving it.

Additional Information: Age Word Problems

Age-related word problems are common in algebra and quantitative aptitude tests. They typically involve relationships between people's ages at different points in time (past, present, future). The key to solving these problems is carefully setting up equations based on the given information for each time period mentioned.

  • Representing Ages: If a person's current age is \(A\), their age \(x\) years ago was \(A - x\), and their age \(y\) years from now will be \(A + y\).
  • Forming Relationships: Look for clues about sums, differences, products, or ratios of ages at different times.
  • Using Multiple Variables: For problems involving two or more people, use a different variable for each person's current age.
  • Consistent Time Frame: Ensure that when forming equations, you are comparing ages at the same point in time (e.g., comparing father's age 5 years from now to son's age 5 years from now).
  • Solving Techniques: Systems of equations can be solved using substitution (as demonstrated above), elimination, or graphical methods. Substitution is often effective for age problems where one variable can easily be expressed in terms of another.

Practicing different types of age problems helps build confidence in translating verbal descriptions into mathematical models.

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Similar Questions

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Important Questions from Quant Based Puzzle

  1. There are deers and peacocks in a zoo. By counting heads they are 80. The number of their legs is 200. How many peacocks are there?
  2. A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 70, how many horses are there?
  3. A, B, C, D and E play a game of cards. A says to B, "If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has". A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have?
  4. A player holds 13 cards of four suits, of which seven are black and six are red. There are twice as many diamonds as spades and twice as many hearts as diamonds. How many clubs does he hold?
  5. 5 years ago, father’s age was 8 times Rohan’s age. 5 years hence, the ratio of father’s age to Rohan’s age will be 10 : 3. What is Rohan’s present age?

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