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Question

The ages of A and B differ by 16 years. If 6 years ago, the elder one was 3 times as old as the younger one, find the present age of the younger between A and B?

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is

14 years

Understanding the Age Difference Problem

This problem involves finding the present age of the younger of two people, A and B, based on two pieces of information: the difference in their present ages and a relationship between their ages six years ago.

We need to set up mathematical equations to represent the given conditions and then solve them to find the required age.

Setting Up Equations for Ages

Let's denote the present age of the younger person as \(Y\) years and the present age of the elder person as \(E\) years.

According to the first condition:

  • The ages of A and B differ by 16 years.
  • This means the difference between the elder's age and the younger's age is 16.

So, we can write the equation:

\(E - Y = 16\)

From this, we can express the elder's age in terms of the younger's age:

\(E = Y + 16\)

Now, let's consider the ages 6 years ago:

  • The younger person's age 6 years ago was \(Y - 6\).
  • The elder person's age 6 years ago was \(E - 6\).

According to the second condition:

  • 6 years ago, the elder one was 3 times as old as the younger one.

So, we can write the equation:

\(E - 6 = 3 \times (Y - 6)\)

Solving the Age Equations

We now have a system of two equations:

  1. \(E = Y + 16\)
  2. \(E - 6 = 3(Y - 6)\)

We can substitute the expression for \(E\) from equation (1) into equation (2):

\((Y + 16) - 6 = 3(Y - 6)\)

Now, simplify and solve for \(Y\):

\(Y + 10 = 3Y - 18\)

To isolate \(Y\) terms on one side and constants on the other, add 18 to both sides and subtract \(Y\) from both sides:

\(10 + 18 = 3Y - Y\)

\(28 = 2Y\)

Now, divide by 2 to find the value of \(Y\):

\(Y = \frac{28}{2}\)

\(Y = 14\)

The value of \(Y\) represents the present age of the younger person.

Verifying the Solution

Let's check if our answer satisfies both conditions:

  • If the younger person's present age (\(Y\)) is 14 years, the elder person's present age (\(E\)) is \(Y + 16 = 14 + 16 = 30\) years.
  • The difference in ages is \(30 - 14 = 16\) years. This matches the first condition.
  • 6 years ago, the younger person's age was \(14 - 6 = 8\) years.
  • 6 years ago, the elder person's age was \(30 - 6 = 24\) years.
  • Is the elder one's age (24) three times the younger one's age (8) 6 years ago? \(3 \times 8 = 24\). Yes, it is. This matches the second condition.

Both conditions are satisfied, so the present age of the younger person is indeed 14 years.

Present Age of the Younger Person

Based on our calculations, the present age of the younger person is 14 years.

Summary of Ages
Present Age Age 6 Years Ago
Younger (Y) 14 14 - 6 = 8
Elder (E) 30 30 - 6 = 24

Checking the conditions:

  • Present difference: \(30 - 14 = 16\). Correct.
  • 6 years ago relationship: \(24 = 3 \times 8\). Correct.

Revision Table: Age Problem Concepts

Key Concepts for Age Problems
Concept Description How it Applies Here
Representing Ages Use variables (e.g., \(x\), \(y\)) for unknown ages. Used \(Y\) for younger, \(E\) for elder.
Ages in the Past/Future To find age \(n\) years ago, subtract \(n\). To find age \(n\) years in future, add \(n\). Used \(Y-6\) and \(E-6\) for ages 6 years ago.
Translating Words to Equations Convert sentences into mathematical expressions (e.g., "differ by" means subtraction, "times as old" means multiplication). Converted "differ by 16" to \(E-Y=16\) and "elder was 3 times as old as younger" to \(E-6 = 3(Y-6)\).
Solving Simultaneous Equations Use substitution or elimination to find the values of the variables. Used substitution to solve for \(Y\).

Additional Information: Solving Word Problems

Solving word problems, especially age problems or problems involving linear equations, often follows a structured approach:

  1. Read Carefully: Understand the problem, identify the knowns and the unknowns. What is the question asking for?
  2. Assign Variables: Use letters to represent the unknown quantities. Be specific (e.g., "let \(x\) be the present age of A").
  3. Formulate Equations: Translate the sentences and conditions given in the problem into mathematical equations using the variables.
  4. Solve the Equations: Use appropriate algebraic methods (like substitution, elimination, simplification) to find the values of the variables.
  5. Answer the Question: Make sure you have found the specific value that the question asked for. Sometimes you solve for a variable, but the question asks for something else (e.g., the sum of ages, or the age in the future).
  6. Verify: Check if your solution makes sense in the context of the original problem and satisfies all the given conditions.

Age problems are common examples of linear equations in one or two variables and are fundamental in algebra.

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Similar Questions

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Important Questions from Quant Based Puzzle

  1. There are deers and peacocks in a zoo. By counting heads they are 80. The number of their legs is 200. How many peacocks are there?
  2. A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 70, how many horses are there?
  3. A, B, C, D and E play a game of cards. A says to B, "If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has". A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have?
  4. A player holds 13 cards of four suits, of which seven are black and six are red. There are twice as many diamonds as spades and twice as many hearts as diamonds. How many clubs does he hold?
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