Pinaki is 9 years younger than Bhaswati. Thirteen years hence Bhaswati will be 1.2 times as old as Pinaki. Find Pinaki's present age.
32 years
This problem involves finding the present age of Pinaki and Bhaswati using the given relationships between their ages now and in the future. We can use algebraic equations to represent these relationships and solve for the unknown ages.
Let's define variables for the present ages:
From the first statement, "Pinaki is 9 years younger than Bhaswati", we can write the equation:
\(P = B - 9\)
This can also be written as \(B = P + 9\). This equation relates their present ages.
Now consider the ages thirteen years from now:
The second statement says, "Thirteen years hence Bhaswati will be 1.2 times as old as Pinaki". We can write this as the equation:
\(B + 13 = 1.2 \times (P + 13)\)
We have two equations:
We can substitute the expression for \(B\) from equation (1) into equation (2):
\((P + 9) + 13 = 1.2 \times (P + 13)\)
Simplify the left side:
\(P + 22 = 1.2 \times (P + 13)\)
Distribute 1.2 on the right side:
\(P + 22 = 1.2P + 1.2 \times 13\)
\(P + 22 = 1.2P + 15.6\)
Now, we need to isolate \(P\). Subtract \(P\) from both sides:
\(22 = 1.2P - P + 15.6\)
\(22 = 0.2P + 15.6\)
Subtract 15.6 from both sides:
\(22 - 15.6 = 0.2P\)
\(6.4 = 0.2P\)
To find \(P\), divide 6.4 by 0.2:
\(P = \frac{6.4}{0.2}\)
\(P = \frac{64}{2}\)
\(P = 32\)
So, Pinaki's present age is 32 years.
Let's check if this answer satisfies the original conditions:
Thirteen years hence:
Is Bhaswati's age 1.2 times Pinaki's age thirteen years hence?
\(1.2 \times 45 = 54\)
Yes, the ages \(54\) and \(45\) satisfy the condition \(54 = 1.2 \times 45\). The solution is correct.
Let's summarize the ages in a table:
| Person | Present Age | Age Thirteen Years Hence |
|---|---|---|
| Pinaki | \(P = 32\) years | \(P + 13 = 45\) years |
| Bhaswati | \(B = 41\) years | \(B + 13 = 54\) years |
The calculated present age for Pinaki is 32 years.
| Concept | Explanation | Example |
|---|---|---|
| Representing Ages | Use variables for present ages. | Let present age be \(x\). |
| Age in the Future | Add the number of years to the present age. | Age after 5 years: \(x + 5\). |
| Age in the Past | Subtract the number of years from the present age. | Age 3 years ago: \(x - 3\). |
| Age Difference | The difference in age between two people remains constant over time. | If A is 5 years older than B now, A will be 5 years older than B in the future too. |
Solving word problems, especially those involving ages, often follows a systematic approach:
Age word problems are a common type of question in quantitative aptitude tests and require careful translation of verbal statements into algebraic expressions.
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