A, B, C, D and E play a game of cards. A says to B, "If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has". A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have?
25
This problem involves determining the number of cards each player has based on several given conditions. We will use algebraic equations to represent these conditions and solve for the unknown quantities.
We are given information about the relative number of cards held by five players: A, B, C, D, and E. Let's denote the number of cards each player has by $n_A, n_B, n_C, n_D,$ and $n_E$ respectively.
Let's translate each condition into a mathematical equation:
We now have a system of 5 linear equations with 5 variables.
Our goal is to find the value of $n_B$. We can express the other variables in terms of $n_B$ and substitute them into the total sum equation (Equation 5).
From Equation 1, we get: $n_E = n_B - 3$.
From Equation 2, we get: $n_D = n_B + 3$.
From Equation 4, we get: $n_C = n_B - 2$.
Now, let's use Equation 3: $n_A + n_B - n_D - n_E = 10$. Substitute the expressions for $n_D$ and $n_E$:
$\qquad n_A + n_B - (n_B + 3) - (n_B - 3) = 10$
$\qquad n_A + n_B - n_B - 3 - n_B + 3 = 10$
$\qquad n_A - n_B = 10$
This gives us an expression for $n_A$ in terms of $n_B$: $n_A = n_B + 10$.
Now we have expressions for $n_A, n_C, n_D,$ and $n_E$ all in terms of $n_B$:
Substitute these expressions into Equation 5 (the total number of cards):
$\qquad (n_B + 10) + n_B + (n_B - 2) + (n_B + 3) + (n_B - 3) = 133$
Combine the terms with $n_B$ and the constant terms:
$\qquad (n_B + n_B + n_B + n_B + n_B) + (10 - 2 + 3 - 3) = 133$
$\qquad 5n_B + 8 = 133$
Now, solve for $n_B$:
$\qquad 5n_B = 133 - 8$
$\qquad 5n_B = 125$
$\qquad n_B = \frac{125}{5}$
$\qquad n_B = 25$
So, B has 25 cards.
Let's find the number of cards for all players based on $n_B = 25$ and check if they satisfy all conditions:
Check conditions:
All conditions are satisfied, confirming our calculated value for $n_B$ is correct.
The number of cards B has is 25.
| Relationship | Equation |
|---|---|
| B gives 3 to A, B has E's cards | $n_B - 3 = n_E$ |
| A gives 3 to B, B has D's cards | $n_B + 3 = n_D$ |
| A & B vs D & E difference | $n_A + n_B = n_D + n_E + 10$ |
| B vs C difference | $n_B = n_C + 2$ |
| Total cards | $n_A + n_B + n_C + n_D + n_E = 133$ |
Word problems often describe relationships between unknown quantities. To solve them using algebra, follow these general steps:
This card game problem is a good example of setting up multiple linear equations and solving them simultaneously, often using substitution to reduce the number of variables.
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