A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 70, how many horses are there?
14
This problem asks us to find the number of horses given information about horses, men, and the total number of legs walking on the ground. We are told that the number of horses and men is equal. We are also given how the men are divided into two groups: those riding horses and those walking and leading their horses. Finally, we have the total count of legs touching the ground.
Let's use a variable to represent the unknown quantity. Since the number of horses and the number of men are equal, we can use one variable for both.
The problem states that half of the owners (men) are on their horses' backs, and the remaining half are walking and leading their horses.
All horses are on the ground, whether they are being ridden or led. So, all $x$ horses contribute to the legs on the ground.
Now let's count the legs from each group that are walking on the ground:
The total number of legs walking on the ground is the sum of the legs from all these sources.
Total legs on the ground = (Legs from walking men) + (Legs from horses being led) + (Legs from horses being ridden)
Total legs on the ground = $x + 2x + 2x = 5x$.
We are given that the total number of legs walking on the ground is 70. So, we can set up an equation:
\begin{equation*} 5x = 70 \end{equation*}
To find the value of $x$, we need to divide both sides of the equation by 5:
\begin{equation*} x = \frac{70}{5} \end{equation*}
\begin{equation*} x = 14 \end{equation*}
The value of $x$ is 14. Since $x$ represents the number of horses, there are 14 horses.
| Group | Number | Legs per individual/animal | Total Legs on Ground |
|---|---|---|---|
| Men walking | $\frac{x}{2}$ | 2 | $\frac{x}{2} \times 2 = x$ |
| Horses being led | $\frac{x}{2}$ | 4 | $\frac{x}{2} \times 4 = 2x$ |
| Horses being ridden | $\frac{x}{2}$ | 4 | $\frac{x}{2} \times 4 = 2x$ |
| Total Legs | $x + 2x + 2x = 5x$ |
Given $5x = 70$, we find $x = 14$. Therefore, there are 14 horses.
| Concept | Description | Application in Problem |
|---|---|---|
| Variable Assignment | Using a letter (e.g., $x$) to represent an unknown quantity. | Letting $x$ be the number of horses (and men). |
| Forming Expressions | Translating word phrases into mathematical expressions. | Expressing groups ($\frac{x}{2}$) and legs ($2x$, $4x$). |
| Setting up Equations | Equating two expressions that represent the same value. | Equating total calculated legs ($5x$) to the given total (70). |
| Solving Linear Equations | Finding the value of the variable in an equation. | Solving $5x = 70$ to find $x=14$. |
Word problems like the horses and men legs problem require careful reading and translating the given information into mathematical terms. Here are some tips for tackling such problems:
In this specific problem, understanding which legs are "walking on the ground" is key. It includes the legs of the walking men and the legs of *all* the horses, as all horses are on the ground.
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