The smallest four-digit number that is exactly divisible by each of 24, 40, and 56 is:
1680
The correct answer is option 3 i.e. 1680.
Step 1 – LCM: \(24 = 2^3 \times 3,\ 40 = 2^3 \times 5,\ 56 = 2^3 \times 7\). LCM \(= 2^3 \times 3 \times 5 \times 7 = 840\).
Step 2 – Smallest 4-digit multiple of 840: \(840 \times 2 = 1680\).
Hence option (3).
Similar Questions
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Important Questions from LCM and HCF
The HCF and LCM of two numbers are 12 and 72, respectively. If the ratio of the two numbers is 2 ∶ 3, then the larger of the two numbers is:
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
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What is the least number which when divided by 12,20 and 24 leaves in each case a remainder of 8?
Which of the following is a pair of co-primes?
