The HCF of the numbers 310, 208, and 180 is:
2
The question asks us to find the Highest Common Factor (HCF), also known as the Greatest Common Divisor (GCD), of the three numbers: 310, 208, and 180.
The HCF is the largest positive integer that divides each of the given numbers without leaving a remainder.
One common method to find the HCF is using prime factorization. We find the prime factors of each number separately.
Start dividing 310 by the smallest prime number, which is 2:
So, the prime factorization of 310 is \(2 \times 5 \times 31\).
Start dividing 208 by 2:
So, the prime factorization of 208 is \(2 \times 2 \times 2 \times 2 \times 13\), which can be written as \(2^4 \times 13\).
Start dividing 180 by 2:
So, the prime factorization of 180 is \(2 \times 2 \times 3 \times 3 \times 5\), which can be written as \(2^2 \times 3^2 \times 5\).
Now, let's list the prime factorizations side-by-side:
We need to find the prime factors that are common to all three numbers. The only prime factor that appears in all three lists is 2.
To find the HCF, we take the lowest power of each common prime factor.
Therefore, the HCF is \(2^1 = 2\).
The Highest Common Factor (HCF) of 310, 208, and 180 is 2.
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