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Question

The HCF of the numbers 310, 208, and 180 is:

This question was previously asked in
RRB NTPC 2024 Undergraduate CBT 1 Question Paper (29-Aug-2025) (Shift 1)
The correct answer is

2

Finding HCF of 310, 208, and 180

The question asks us to find the Highest Common Factor (HCF), also known as the Greatest Common Divisor (GCD), of the three numbers: 310, 208, and 180.

The HCF is the largest positive integer that divides each of the given numbers without leaving a remainder.

Method: Prime Factorization

One common method to find the HCF is using prime factorization. We find the prime factors of each number separately.

Prime Factorization of 310

Start dividing 310 by the smallest prime number, which is 2:

  • \(310 \div 2 = 155\)
  • Now, check if 155 is divisible by the next prime numbers. It's not divisible by 3 (1+5+5=11). It is divisible by 5:
  • \(155 \div 5 = 31\)
  • 31 is a prime number.

So, the prime factorization of 310 is \(2 \times 5 \times 31\).

Prime Factorization of 208

Start dividing 208 by 2:

  • \(208 \div 2 = 104\)
  • \(104 \div 2 = 52\)
  • \(52 \div 2 = 26\)
  • \(26 \div 2 = 13\)
  • 13 is a prime number.

So, the prime factorization of 208 is \(2 \times 2 \times 2 \times 2 \times 13\), which can be written as \(2^4 \times 13\).

Prime Factorization of 180

Start dividing 180 by 2:

  • \(180 \div 2 = 90\)
  • \(90 \div 2 = 45\)
  • 45 is not divisible by 2. Check the next prime number, 3:
  • \(45 \div 3 = 15\)
  • \(15 \div 3 = 5\)
  • 5 is a prime number.

So, the prime factorization of 180 is \(2 \times 2 \times 3 \times 3 \times 5\), which can be written as \(2^2 \times 3^2 \times 5\).

Identifying Common Factors

Now, let's list the prime factorizations side-by-side:

  • \(310 = 2 \times 5 \times 31\)
  • \(208 = 2^4 \times 13\)
  • \(180 = 2^2 \times 3^2 \times 5\)

We need to find the prime factors that are common to all three numbers. The only prime factor that appears in all three lists is 2.

Calculating the HCF

To find the HCF, we take the lowest power of each common prime factor.

  • The prime factor 2 appears in the factorizations as \(2^1\) (in 310), \(2^4\) (in 208), and \(2^2\) (in 180).
  • The lowest power of 2 among these is \(2^1\).
  • There are no other common prime factors.

Therefore, the HCF is \(2^1 = 2\).

Conclusion

The Highest Common Factor (HCF) of 310, 208, and 180 is 2.

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Similar Questions

  1. If LCM(27, n) = 54, and HCF(27, n) = 9, then the value of n is:

  2. The highest common factor of a set of coprime numbers is equal to:

  3. Two numbers are in ratio 3 : 2. Their LCM and HCF are 24 and 4, respectively. Find the greater number.

  4. The LCM of two numbers is 84. If the numbers are in the ratio 2 : 3, then the sum of the numbers is:

  5. What is the least positive number that can be added to 2488 so that it is completely divisible by 3, 4, 5, and 6?

  6. Find the least number which when divided by 5, 6 and 7 leaves remainders 4, 5 and 6.
  7. Find the HCF of 24, 36 and 102.
  8. The HCF of two numbers is 9 and their LCM is 252. The sum of numbers is:

  9. What is the difference between the HCF and LCM of 184 and 345?
  10. The HCF of two numbers is 9 and their LCM is 252. The sum of numbers is:

Important Questions from LCM and HCF

  1. The HCF and LCM of two numbers are 12 and 72, respectively. If the ratio of the two numbers is 2 ∶ 3, then the larger of the two numbers is:

  2. Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

  3. Joseph visits the club on every 5 th day, Harsh visits on every 24 th day, while Sumit visits on every 9 th day. If all three of them met at the club on a Sunday, then on which day will all three of them meet again?

  4. What is the least number which when divided by 12,20 and 24 leaves in each case a remainder of 8?

  5. Which of the following is a pair of co-primes?

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