If LCM(27, n) = 54, and HCF(27, n) = 9, then the value of n is:
18
This problem asks us to find the value of an unknown number, represented by 'n', given the Least Common Multiple (LCM) and Highest Common Factor (HCF) of 27 and 'n'. We are provided with the following information:
There's a fundamental property that connects two numbers (let's call them 'a' and 'b') with their LCM and HCF. This property states that the product of the two numbers is equal to the product of their LCM and HCF.
Mathematically, this is represented as:
\(a \times b = \text{HCF}(a, b) \times \text{LCM}(a, b)\)
In this specific problem, we have:
Let's substitute these values into the formula:
\(27 \times n = \text{HCF}(27, n) \times \text{LCM}(27, n)\)
\(27 \times n = 9 \times 54\)
First, calculate the product of the HCF and LCM:
\(9 \times 54 = 486\)
Now, our equation becomes:
\(27 \times n = 486\)
To find 'n', we need to divide 486 by 27:
\(n = \frac{486}{27}\)
Performing the division:
\(n = 18\)
Let's check if \(n = 18\) satisfies the given conditions:
Since both conditions are met, the calculated value of \(n = 18\) is correct.
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