We are given the Highest Common Factor (HCF) and Lowest Common Multiple (LCM) of two numbers. We need to find their sum.
Let the two numbers be \(a\) and \(b\). The fundamental relationship between two numbers, their HCF, and LCM is:
\( HCF(a, b) \times LCM(a, b) = a \times b \)Given:
Using the formula, the product of the two numbers is:
\( a \times b = 9 \times 252 \) \( a \times b = 2268 \)Since the HCF of the numbers is 9, both numbers must be multiples of 9. We can represent the numbers as \(a = 9x\) and \(b = 9y\), where \(x\) and \(y\) are coprime integers (meaning \(HCF(x, y) = 1\)).
Substitute these into the product equation:
\( (9x) \times (9y) = 2268 \) \( 81xy = 2268 \)Now, solve for the product \(xy\):
\( xy = \frac{2268}{81} \) \( xy = 28 \)We need to find pairs of coprime integers (\(x, y\)) whose product is 28.
The pairs of factors for 28 are (1, 28), (2, 14), and (4, 7).
Let's check which pairs are coprime:
The coprime pairs \((x, y)\) are (1, 28) and (4, 7).
Now, let's find the numbers and their sums for each coprime pair:
Comparing these sums with the given options, the sum 99 is present.
Final Answer: The sum of the numbers is 99.
The HCF of the numbers 310, 208, and 180 is:
If LCM(27, n) = 54, and HCF(27, n) = 9, then the value of n is:
The highest common factor of a set of coprime numbers is equal to:
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The HCF of two numbers is 9 and their LCM is 252. The sum of numbers is:
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Joseph visits the club on every 5 th day, Harsh visits on every 24 th day, while Sumit visits on every 9 th day. If all three of them met at the club on a Sunday, then on which day will all three of them meet again?
What is the least number which when divided by 12,20 and 24 leaves in each case a remainder of 8?
Which of the following is a pair of co-primes?