The goal is to identify the smallest integer that has five digits and is exactly divisible by 12, 16, 24, and 28.
To find a number divisible by all the given numbers (12, 16, 24, 28), we first calculate their LCM. This is the smallest positive number that is a multiple of all of them.
Find the prime factorization of each number:
The LCM is the product of the highest powers of all prime factors involved:
LCM$(12, 16, 24, 28) = 2^4 \times 3^1 \times 7^1 = 16 \times 3 \times 7 = 336$.
The smallest five-digit number is 10000.
To find the smallest five-digit number divisible by 336, we divide 10000 by 336 and find the next whole number multiple.
$ \frac{10000}{336} \approx 29.76 $
The next integer after 29.76 is 30. This means the 30th multiple of 336 is the smallest multiple that is a five-digit number.
Calculate the 30th multiple:
$ 30 \times 336 = 10080 $
The smallest five-digit number divisible by 12, 16, 24, and 28 is 10080.
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