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Question

The ratio of the present ages of Asha and Lata is 5 : 6. If the difference between their ages is 6 years, then what will be Lata’s age after 5 years?

This question was previously asked in
SSC CGL 2019 (Tier 2) GS Finance & Economics Previous Year Paper (17-Nov-2020)
The correct answer is

41

Solving Age Ratio Problems: Finding Future Age

This problem involves finding the future age of a person based on the ratio of present ages and the difference between them. We are given the ratio of the present ages of Asha and Lata and the difference in their ages. We need to calculate Lata's age after 5 years.

Let's break down the problem and solve it step-by-step.

Understanding the Age Ratio

The present ages of Asha and Lata are in the ratio 5 : 6. This means that for some common multiplier, let's call it \(x\), Asha's age is \(5x\) years and Lata's age is \(6x\) years.

  • Asha's present age = \(5x\) years
  • Lata's present age = \(6x\) years

Since the ratio is 5:6, Lata is currently older than Asha. The difference in their ages is given as 6 years.

Using the Age Difference to Find the Multiplier

The difference between their ages is the difference between the larger age (Lata's) and the smaller age (Asha's).

Difference in ages = Lata's present age - Asha's present age

We are given this difference is 6 years.

So, we can set up the equation:

\(6x - 5x = 6\)

Now, we solve for \(x\):

\(x = 6\)

The common multiplier \(x\) is 6.

Calculating Present Ages

Now that we know the value of \(x\), we can find the present ages of Asha and Lata:

  • Asha's present age = \(5x = 5 \times 6 = 30\) years
  • Lata's present age = \(6x = 6 \times 6 = 36\) years

We can quickly check the difference: \(36 - 30 = 6\), which matches the information given in the problem.

Calculating Lata's Age After 5 Years

The question asks for Lata's age after 5 years. To find this, we add 5 years to Lata's present age.

Lata's age after 5 years = Lata's present age + 5 years

Lata's age after 5 years = \(36 + 5 = 41\) years

Summary of Calculations

Step Description Calculation Result
1 Represent ages using ratio Asha: \(5x\), Lata: \(6x\) Asha: \(5x\), Lata: \(6x\)
2 Set up equation from difference \(6x - 5x = 6\) \(x = 6\)
3 Calculate present ages Asha: \(5 \times 6\), Lata: \(6 \times 6\) Asha: 30, Lata: 36
4 Calculate Lata's age after 5 years \(36 + 5\) 41

Therefore, Lata's age after 5 years will be 41 years.

Revision Table: Key Concepts

Concept Explanation
Ratio of Ages Represents the proportional relationship between the ages of two or more people at a specific point in time. If the ratio is \(a:b\), ages can be represented as \(ax\) and \(bx\).
Age Difference The difference in age between two people remains constant throughout their lives. If the difference is \(D\) and ages are \(ax\) and \(bx\) (\(b > a\)), then \(bx - ax = D\).
Future Age To find someone's age after \(N\) years, add \(N\) to their present age. Present age + \(N\) years = Future age.

Additional Information: Solving Age Problems

Age-related problems often involve ratios, sums, or differences of ages at different points in time (past, present, or future). Here are some common types and approaches:

  • Age Sum Problems: If the sum of ages is given, say \(S\), and the ratio is \(a:b\), then \(ax + bx = S\). Solve for \(x\) and find the ages.
  • Problems with Past/Future Ages: If the ratio or sum is given for a past time (say, \(Y\) years ago) or a future time (say, \(Z\) years from now), adjust the present ages accordingly before setting up the equation.
    • Age \(Y\) years ago = Present age - \(Y\)
    • Age \(Z\) years from now = Present age + \(Z\)
  • Using one variable: Sometimes, if the difference is given directly (e.g., A is 6 years older than B), you can represent ages as \(B\) and \(B+6\) without using a ratio multiplier initially, depending on the problem structure.

Always carefully read whether the given information (ratio, sum, difference) refers to present ages, past ages, or future ages.

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  4. A player holds 13 cards of four suits, of which seven are black and six are red. There are twice as many diamonds as spades and twice as many hearts as diamonds. How many clubs does he hold?
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