Let's calculate the percentage increase in the area of a circle when its radius increases. We are given the original radius and the new radius, and we need to find how much the area has increased in terms of percentage.
The area of a circle is calculated using the formula:
\(A = \pi r^2\)
where:
To find the percentage increase in area, we first need to calculate the original area and the new area.
The original radius of the circle is given as 90 cm.
Original Radius (\(r_1\)) = 90 cm
Original Area (\(A_1\)) = \(\pi r_1^2 = \pi (90 \text{ cm})^2\)
\(A_1 = \pi \times 8100 \text{ cm}^2\)
\(A_1 = 8100\pi \text{ cm}^2\)
The radius is increased to 99 cm.
New Radius (\(r_2\)) = 99 cm
New Area (\(A_2\)) = \(\pi r_2^2 = \pi (99 \text{ cm})^2\)
\(A_2 = \pi \times (99 \times 99) \text{ cm}^2\)
\(A_2 = \pi \times 9801 \text{ cm}^2\)
\(A_2 = 9801\pi \text{ cm}^2\)
The increase in area is the difference between the new area and the original area.
Increase in Area = \(A_2 - A_1\)
Increase in Area = \(9801\pi \text{ cm}^2 - 8100\pi \text{ cm}^2\)
Increase in Area = \((9801 - 8100)\pi \text{ cm}^2\)
Increase in Area = \(1701\pi \text{ cm}^2\)
The percentage increase is calculated by dividing the increase in area by the original area and multiplying by 100.
Percentage Increase = \(\frac{\text{Increase in Area}}{\text{Original Area}} \times 100\)
Percentage Increase = \(\frac{1701\pi \text{ cm}^2}{8100\pi \text{ cm}^2} \times 100\)
Notice that \(\pi\) cancels out from the numerator and the denominator.
Percentage Increase = \(\frac{1701}{8100} \times 100\)
Let's simplify the fraction \(\frac{1701}{8100}\). Both numbers are divisible by 9.
\(1701 \div 9 = 189\)
\(8100 \div 9 = 900\)
So, the fraction is \(\frac{189}{900}\). Both numbers are still divisible by 9.
\(189 \div 9 = 21\)
\(900 \div 9 = 100\)
The simplified fraction is \(\frac{21}{100}\).
Percentage Increase = \(\frac{21}{100} \times 100\)
Percentage Increase = \(21\)
So, the percentage increase in the area of the circle is 21%.
| Parameter | Value | Calculation |
|---|---|---|
| Original Radius (\(r_1\)) | 90 cm | Given |
| Original Area (\(A_1\)) | \(8100\pi\) cm<sup>2</sup> | \(\pi \times 90^2\) |
| New Radius (\(r_2\)) | 99 cm | Given |
| New Area (\(A_2\)) | \(9801\pi\) cm<sup>2</sup> | \(\pi \times 99^2\) |
| Increase in Area (\(\Delta A\)) | \(1701\pi\) cm<sup>2</sup> | \(A_2 - A_1\) |
| Percentage Increase | 21% | \(\frac{\Delta A}{A_1} \times 100\) |
Let the original radius be \(r\). The original area is \(A = \pi r^2\).
The radius increases from 90 cm to 99 cm.
Percentage increase in radius = \(\frac{\text{Increase in Radius}}{\text{Original Radius}} \times 100\)
Increase in Radius = 99 cm - 90 cm = 9 cm
Percentage increase in radius = \(\frac{9}{90} \times 100 = \frac{1}{10} \times 100 = 10\%\)
So, the new radius is \(r_{new} = r + 10\% \text{ of } r = r + 0.10r = 1.10r\).
The new area is \(A_{new} = \pi (r_{new})^2 = \pi (1.10r)^2 = \pi (1.10)^2 r^2\).
\(A_{new} = \pi (1.21) r^2 = 1.21 (\pi r^2)\)
Since the original area is \(A = \pi r^2\), the new area is \(1.21 A\).
The increase in area is \(A_{new} - A = 1.21 A - A = 0.21 A\).
Percentage increase in area = \(\frac{0.21 A}{A} \times 100 = 0.21 \times 100 = 21\%\).
This confirms the previous calculation. A 10% increase in radius leads to a (1.10)^2 = 1.21 times increase in area, which is a 21% increase.
| Concept | Formula | Application |
|---|---|---|
| Area of Circle | \(A = \pi r^2\) | Used to find original and new areas. |
| Percentage Increase | \(\frac{\text{Change}}{\text{Original}} \times 100\%\) | Used to find the percentage increase in area. |
| Radius Increase effect on Area | If radius increases by x%, new area is proportional to \((1 + x/100)^2\) | \(10\%\) radius increase \(\rightarrow\) \((1+0.1)^2 = 1.21\) factor increase in area \(\rightarrow\) \(21\%\) area increase. |
Understanding how changes in dimensions affect area and volume is important in geometry.
These principles apply to many geometric shapes, not just circles.
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