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Question

The ratio of the monthly incomes of A and B is 11 : 13 and the ratio of their expenditures is 9 : 11. If both of them manage to save Rs. 4,000 per month, then find the difference in their incomes (in Rs.)

This question was previously asked in
SSC CGL 2020 (Tier-2) Statistics Previous Year Paper 3 (28-Jan-2022)
The correct answer is

4,000

Solving Income and Expenditure Ratio Problems

This problem involves the concepts of ratios, income, expenditure, and savings. We are given the ratios of the monthly incomes and expenditures of two individuals, A and B, along with their monthly savings. We need to find the difference between their monthly incomes.

Setting up Variables and Equations

Let's represent the incomes and expenditures using variables based on the given ratios:

  • The ratio of the monthly incomes of A and B is 11 : 13. We can assume their monthly incomes are \(11x\) and \(13x\) rupees respectively, where \(x\) is a common multiplier.
  • The ratio of their expenditures is 9 : 11. We can assume their monthly expenditures are \(9y\) and \(11y\) rupees respectively, where \(y\) is another common multiplier.

We know that Savings = Income - Expenditure. Both A and B manage to save Rs. 4,000 per month. This gives us two linear equations:

  1. For A: Income of A - Expenditure of A = Savings of A
  2. \($11x - 9y = 4000$\) (Equation 1)
  3. For B: Income of B - Expenditure of B = Savings of B
  4. \($13x - 11y = 4000$\) (Equation 2)

We now have a system of two linear equations with two variables, \(x\) and \(y\).

Solving the System of Equations

We can solve this system using the elimination method. Our goal is to find the value of \(x\) to determine the incomes. Let's eliminate \(y\).

  • Multiply Equation 1 by 11:
  • \($11 \times (11x - 9y) = 11 \times 4000$\)
  • \($121x - 99y = 44000$\) (Equation 3)
  • Multiply Equation 2 by 9:
  • \($9 \times (13x - 11y) = 9 \times 4000$\)
  • \($117x - 99y = 36000$\) (Equation 4)

Now, subtract Equation 4 from Equation 3:

\((121x - 99y) - (117x - 99y) = 44000 - 36000\)

\($121x - 99y - 117x + 99y = 8000$\)

\($121x - 117x = 8000$\)

\($4x = 8000$\)

\($x = \frac{8000}{4}$\)

\($x = 2000$\)

We have found the value of \(x\).

Calculating Incomes and Their Difference

Now we can find the monthly incomes of A and B using the value of \(x\):

  • Monthly income of A = \(11x = 11 \times 2000 = 22000\) rupees.
  • Monthly income of B = \(13x = 13 \times 2000 = 26000\) rupees.

The question asks for the difference in their incomes. The difference is:

Difference = Income of B - Income of A

Difference = \(26000 - 22000\)

Difference = \(4000\) rupees.

Thus, the difference in their monthly incomes is Rs. 4,000.

Revision Table: Key Information

Item A B
Income Ratio 11 13
Expenditure Ratio 9 11
Assumed Income \(11x\) \(13x\)
Assumed Expenditure \(9y\) \(11y\)
Savings 4000 4000
Actual Income (using \(x=2000\)) 22000 26000
Actual Expenditure (using \(y=2000\)) 18000 22000

Additional Information: Ratios and Financial Concepts

Understanding ratios and basic financial equations (Income - Expenditure = Savings) is crucial for solving such problems. Here's a little more detail:

  • Ratio: A ratio is a comparison of two or more quantities of the same kind by division. If a ratio is \(a:b\), it means the first quantity is \(\frac{a}{b}\) times the second quantity. When solving problems, we often represent quantities in a given ratio \(a:b\) as \(ax\) and \(bx\), where \(x\) is a non-zero common factor.
  • Income: The money one receives, usually periodically, in exchange for labor, goods, or services.
  • Expenditure: The amount of money spent on goods and services.
  • Savings: The portion of income that is not spent on current consumption. It's calculated as Income - Expenditure.
  • System of Linear Equations: When you have two or more linear equations involving the same variables, it's called a system of linear equations. These can often be solved to find the values of the variables that satisfy all equations simultaneously. Methods include substitution, elimination, and graphical methods. In this problem, we used the elimination method.

Problems involving income, expenditure, and savings ratios are common in competitive exams and test one's ability to translate word problems into mathematical equations and solve them.

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Similar Questions

  1. A family income is Rs. 35,000 in a month. The family spends the income on various expenditures, viz., food, health, education, entertainment, and rent. After incurring all the expenditures, 8% is saved every month. The expenditure on health is 50% more than that of food. While food is three times of the expenditure on entertainment, the expenditure on health is half of the expenditure on education. The expenditure on rent is one-third of the combined expenditure on food, health and education. How much expenditure (in Rs.) is incurred on education?

  2. Two numbers are in the ratio 2 : 3. If 5 is subtracted from the first number and six is added to the second number, then the ratio becomes 5 : 12. What would the ratio become when eight is added to each number?

  3. The ratio of number of cans of orange, pineapple and mixed fruit juices kept in a store is 8 : 9 : 15. If the store sells 25%, 33.33% and 20% of orange, pineapple and mixed fruit juices cans respectively, then what is the ratio of number of cans of these juices in the remaining stock?

  4. The ratio of monthly incomes of A and B is 4 ∶ 5 and that of their monthly expenditures is 3 ∶ 8. If the income of A is equal to the expenditure of B, then what is the ratio of savings of A and B?

  5. The train ticket fare from places A to B in 2 nd class AC and 3 rd class AC is Rs. 2,500 and Rs. 2,000, respectively. If the fares of 2 nd class AC and 3 rd class AC are increased by 20% and 10%, respectively, then find the ratio of the new fares of 2 nd class AC and 3 rd class AC.

  6. In an examination, the number of students who passed and the number of students who failed were in the ratio 25 ∶ 4. If one more student had appeared and passed and the number of failed students was 3 less than earlier, the ratio of passed students to failed students would have become 22 ∶ 3. What is the difference between the number of students who, initially, passed the examination and the number of students who failed the examination?

  7. If (5a – 3b) : (4a – 2b) = 2 : 3, then a : b is equal to:

  8. The ratio of boys and girls in a school is 27 : 23. If the difference between the number of boys and girls is 200, then find the number of boys.

  9. The sum of weights of A and B is 80 kg. 50% of A's weight is \(\frac 5 6\)  times the weights of B. Find the difference between their weights.

  10. The total number of students in a class is 65. If the total number of girls in class 35, then the ratio of the total number of boys to the number of girls is:


Important Questions from Simple Ratios

  1. If the value of \(\frac{{p - q}}{q} = \frac{4}{3}\)  .find p : q

  2. Half of the villagers of a certain village have their own houses. One-fifth of the villagers cultivate paddy. One-third of the villagers are literate. Four-fifth of the villagers are under 25 years of age. Which one of the following statements is certainly correct ?

  3. The two numbers are in the ratio of 9 ∶ 7 and the difference between of these two number is 6000. What is the sum of the two numbers?

  4. A certain number is added to each of a pair of numbers which are in the ratio 4 ∶ 5. The sum of the resulting numbers is 39 and their ratio (taken in the same order as mentioned above) is 6 ∶ 7. What is the number added?

  5. If (p + q) ∶ (q + r) ∶ (r + p) = 5 ∶ 6 ∶ 7 and p + q + r = 18, find the value of p ∶ q ∶ r

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