If (p + q) ∶ (q + r) ∶ (r + p) = 5 ∶ 6 ∶ 7 and p + q + r = 18, find the value of p ∶ q ∶ r
9 ∶ 6 ∶ 12
The problem provides us with ratios involving the sums of three variables, p, q, and r, and also gives us the total sum of these variables. We are asked to find the ratio p : q : r.
The given information is:
We need to find the ratio p ∶ q ∶ r.
From the first ratio, we can introduce a constant multiplier, let's call it 'k'. This means:
We can add the three equations above:
\((p + q) + (q + r) + (r + p) = 5k + 6k + 7k\)
\(2p + 2q + 2r = 18k\)
\(2(p + q + r) = 18k\)
Dividing by 2, we get:
\(p + q + r = 9k\) (Equation 4)
Now, we can find expressions for p, q, and r individually by subtracting Equations 1, 2, and 3 from Equation 4:
So, from the ratio of sums, we find that p = 3k, q = 2k, and r = 4k.
The ratio p ∶ q ∶ r is therefore \(3k \ratio; 2k \ratio; 4k\), which simplifies to \(3 \ratio; 2 \ratio; 4\).
We are given that p + q + r = 18.
Substitute the expressions for p, q, and r in terms of k into this equation:
\(3k + 2k + 4k = 18\)
\(9k = 18\)
Dividing by 9:
\(k = \frac{18}{9} = 2\)
Now that we have the value of k, we can find the actual values of p, q, and r:
The actual values that satisfy both conditions are p=6, q=4, and r=8. Let's check:
The ratio p ∶ q ∶ r is \(6 \ratio; 4 \ratio; 8\).
This ratio can be simplified by dividing all terms by their greatest common divisor, which is 2:
\(\frac{6}{2} \ratio; \frac{4}{2} \ratio; \frac{8}{2} = 3 \ratio; 2 \ratio; 4\)
The ratio p ∶ q ∶ r is \(3 \ratio; 2 \ratio; 4\).
Now let's look at the given options. The options are 4 ∶ 5 ∶ 6, 5 ∶ 6 ∶ 7, 9 ∶ 6 ∶ 12, and 2 ∶ 3 ∶ 4.
Our derived ratio is \(3 \ratio; 2 \ratio; 4\).
Let's examine the third option: \(9 \ratio; 6 \ratio; 12\).
We can see that \(9 \ratio; 6 \ratio; 12\) is proportional to \(3 \ratio; 2 \ratio; 4\), as \(3 \times 3 = 9\), \(2 \times 3 = 6\), and \(4 \times 3 = 12\). So, \(9 \ratio; 6 \ratio; 12\) is \(3 \times (3 \ratio; 2 \ratio; 4)\).
Therefore, the ratio p ∶ q ∶ r is \(9 \ratio; 6 \ratio; 12\).
| Step | Description | Application to this Problem |
|---|---|---|
| 1 | Set up equations from given ratios using a constant (e.g., k). | p+q=5k, q+r=6k, r+p=7k |
| 2 | Sum the equations from Step 1 to find the sum of variables in terms of the constant. | 2(p+q+r) = 18k ∴ p+q+r = 9k |
| 3 | Solve for individual variables in terms of the constant using the sum from Step 2 and initial equations. | p=(p+q+r)-(q+r)=9k-6k=3k q=(p+q+r)-(r+p)=9k-7k=2k r=(p+q+r)-(p+q)=9k-5k=4k |
| 4 | Determine the fundamental ratio p:q:r from the results of Step 3. | p:q:r = 3k:2k:4k = 3:2:4 |
| 5 | Use the given total sum of variables to find the value of the constant. | p+q+r=18 ∴ 9k=18 ∴ k=2 |
| 6 | Substitute the constant's value to find the actual values of p, q, r (if needed). | p=3(2)=6, q=2(2)=4, r=4(2)=8 |
| 7 | Confirm the ratio of actual values and check options for proportionality. | 6:4:8 = 3:2:4. Option 9:6:12 is 3 × (3:2:4). |
A ratio represents a relationship between quantities. For example, the ratio 3:2:4 means that the quantities are in the proportion 3 parts, 2 parts, and 4 parts, for a total of 3+2+4 = 9 parts. The actual values could be 3, 2, 4 (if the total is 9), or 6, 4, 8 (if the total is 18, as 9 parts = 18, so 1 part = 2), or 9, 6, 12 (if the total is 27, as 9 parts = 27, so 1 part = 3), and so on.
All ratios like 3:2:4, 6:4:8, 9:6:12, etc., are considered equivalent because they represent the same relative proportion between the quantities. They are all scalar multiples of the simplest form (3:2:4).
In this problem, our calculations based on the given conditions lead directly to the ratio 3:2:4 (or actual values 6, 4, 8 which have the ratio 3:2:4). However, the option provided as the correct answer is 9:6:12. This ratio 9:6:12 is a proportional representation of the ratio 3:2:4, obtained by multiplying each term by 3. Often, ratio problems might list a scaled version of the simplest ratio as an option.
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