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Question

The ratio of boys and girls in a school is 27 : 23. If the difference between the number of boys and girls is 200, then find the number of boys.

This question was previously asked in
SSC CGL 2019 (Tier 2) GS Finance & Economics Previous Year Paper (17-Nov-2020)
The correct answer is

1350

Solving Ratio Problems: Boys and Girls in School

This problem involves finding the number of boys in a school given the ratio of boys to girls and the difference between their numbers. Let's break down the steps to solve this ratio problem.

Understanding the Ratio of Boys and Girls

The ratio of boys and girls in the school is given as 27 : 23. This means that for every 27 boys, there are 23 girls. We can represent the number of boys and girls using a common multiple.

  • Let the common multiple be \(x\).
  • Number of boys = \(27x\)
  • Number of girls = \(23x\)

Analyzing the Difference in Numbers

We are given that the difference between the number of boys and girls is 200. Since the ratio of boys (27) is greater than the ratio of girls (23), the number of boys is greater than the number of girls. The difference can be expressed as:

Number of boys - Number of girls = 200

Substituting the expressions in terms of \(x\):

\(27x - 23x = 200\)

Solving for the Common Multiple

Now, we solve the equation for \(x\):

\(27x - 23x = 200\)

\(4x = 200\)

To find \(x\), divide both sides by 4:

\(x = \frac{200}{4}\)

\(x = 50\)

The common multiple \(x\) is 50.

Calculating the Number of Boys

The number of boys is given by \(27x\). Now we substitute the value of \(x\) we found:

Number of boys = \(27 \times 50\)

Number of boys = \(1350\)

Verifying the Solution

Let's find the number of girls and check the difference:

  • Number of girls = \(23x = 23 \times 50 = 1150\)
  • Difference = Number of boys - Number of girls = \(1350 - 1150 = 200\)

The calculated difference (200) matches the given difference in the problem, so our calculation for the number of boys is correct.

Therefore, the number of boys in the school is 1350.

Item Ratio Part Expression (with \(x\)) Actual Number (with \(x=50\))
Boys 27 \(27x\) \(27 \times 50 = 1350\)
Girls 23 \(23x\) \(23 \times 50 = 1150\)
Difference \(27-23=4\) \(4x\) \(1350 - 1150 = 200\) (Given)

Revision Table: Key Concepts in Ratio Problems

Concept Description How it applies here
Ratio A comparison of two or more quantities of the same kind, expressed as a:b. The ratio of boys to girls is 27:23.
Parts of a Ratio The numbers in a ratio represent parts of a whole or parts being compared. 27 parts for boys, 23 parts for girls.
Common Multiple (\(x\)) A value that, when multiplied by the ratio parts, gives the actual quantities. Used as \(27x\) and \(23x\) to represent actual numbers of boys and girls.
Difference in Ratio Parts The difference between the ratio parts corresponds to the difference in the actual quantities. Difference in parts is \(27-23=4\), which corresponds to the difference of 200. So, \(4x=200\).

Additional Information on Ratio and Proportion

Ratios are fundamental in mathematics and are used to compare quantities. A proportion is an equation stating that two ratios are equal. Understanding ratios helps in solving various real-world problems involving comparisons, scaling, and distribution.

  • Ratio Simplification: Ratios can be simplified by dividing all parts by their greatest common divisor (GCD). The ratio 27:23 is already in its simplest form as 27 and 23 have no common factors other than 1.
  • Total Quantity: If the total number of students was given, say \(T\), and the ratio is 27:23, the total parts would be \(27+23=50\). The number of boys would be \(\frac{27}{50} \times T\) and girls \(\frac{23}{50} \times T\). In this problem, we used the difference instead of the total.
  • Applications: Ratios are used in various fields like cooking (recipes), map scales, financial analysis, and mixing chemicals.
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Similar Questions

  1. A family income is Rs. 35,000 in a month. The family spends the income on various expenditures, viz., food, health, education, entertainment, and rent. After incurring all the expenditures, 8% is saved every month. The expenditure on health is 50% more than that of food. While food is three times of the expenditure on entertainment, the expenditure on health is half of the expenditure on education. The expenditure on rent is one-third of the combined expenditure on food, health and education. How much expenditure (in Rs.) is incurred on education?

  2. Two numbers are in the ratio 2 : 3. If 5 is subtracted from the first number and six is added to the second number, then the ratio becomes 5 : 12. What would the ratio become when eight is added to each number?

  3. The ratio of number of cans of orange, pineapple and mixed fruit juices kept in a store is 8 : 9 : 15. If the store sells 25%, 33.33% and 20% of orange, pineapple and mixed fruit juices cans respectively, then what is the ratio of number of cans of these juices in the remaining stock?

  4. The ratio of monthly incomes of A and B is 4 ∶ 5 and that of their monthly expenditures is 3 ∶ 8. If the income of A is equal to the expenditure of B, then what is the ratio of savings of A and B?

  5. The train ticket fare from places A to B in 2 nd class AC and 3 rd class AC is Rs. 2,500 and Rs. 2,000, respectively. If the fares of 2 nd class AC and 3 rd class AC are increased by 20% and 10%, respectively, then find the ratio of the new fares of 2 nd class AC and 3 rd class AC.

  6. The ratio of the monthly incomes of A and B is 11 : 13 and the ratio of their expenditures is 9 : 11. If both of them manage to save Rs. 4,000 per month, then find the difference in their incomes (in Rs.)

  7. In an examination, the number of students who passed and the number of students who failed were in the ratio 25 ∶ 4. If one more student had appeared and passed and the number of failed students was 3 less than earlier, the ratio of passed students to failed students would have become 22 ∶ 3. What is the difference between the number of students who, initially, passed the examination and the number of students who failed the examination?

  8. If (5a – 3b) : (4a – 2b) = 2 : 3, then a : b is equal to:

  9. The sum of weights of A and B is 80 kg. 50% of A's weight is \(\frac 5 6\)  times the weights of B. Find the difference between their weights.

  10. The total number of students in a class is 65. If the total number of girls in class 35, then the ratio of the total number of boys to the number of girls is:


Important Questions from Simple Ratios

  1. If the value of \(\frac{{p - q}}{q} = \frac{4}{3}\)  .find p : q

  2. Half of the villagers of a certain village have their own houses. One-fifth of the villagers cultivate paddy. One-third of the villagers are literate. Four-fifth of the villagers are under 25 years of age. Which one of the following statements is certainly correct ?

  3. The two numbers are in the ratio of 9 ∶ 7 and the difference between of these two number is 6000. What is the sum of the two numbers?

  4. A certain number is added to each of a pair of numbers which are in the ratio 4 ∶ 5. The sum of the resulting numbers is 39 and their ratio (taken in the same order as mentioned above) is 6 ∶ 7. What is the number added?

  5. If (p + q) ∶ (q + r) ∶ (r + p) = 5 ∶ 6 ∶ 7 and p + q + r = 18, find the value of p ∶ q ∶ r

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