The perimeter of a rectangle is 56 cm. Its length is 4 cm more than twice its breadth. Find the breadth.
8 cm
Let the breadth be \(b\) cm. The length is 4 cm more than twice the breadth, so length \(= 2b + 4\).
The perimeter of a rectangle is \(2(\text{length} + \text{breadth})\), which equals 56.
Set up the equation: \(2((2b + 4) + b) = 56\), so \((3b + 4) = 28\).
Solve: \(3b = 24\), giving \(b = 8\).
Hence, the breadth of the rectangle is 8 cm.
The shorter side of a rectangle is 15 cm less than the longer side. The numerical value of its area is equal to 5 times the numerical value of its perimeter. What is the length (in cm) of its longer side?