The minimum power required to lift a mass of 50 kg up to a vertical distance of 8 m in 10 s is: (Take g = 10 m/s²)
400 W
Using the formula for work done: Work = mgh
Work = 50 × 10 × 8 = 4000 J
Power = Work/Time = 4000 J / 10 s = 400 W.
The minimum power required is 400 W, so the correct answer is (a) 400 W.
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