A motorcycle has an initial velocity of 5 m/s. After 3 seconds, the velocity is 7 m/s. The displacement of the motorcycle in 3 seconds is:
18 m
Given, u = 5 m/s, v = 7 m/s, and t = 3 seconds.
Using the equation of motion: v = u + at
7 = 5 + a × 3
Solving for acceleration: a = (7 - 5) / 3 = 2 / 3 = 0.67 m/s²
Now, using the equation for displacement: s = ut + 1/2 at²
s = 5 × 3 + 1/2 × 0.67 × (3)² = 15 + 3 = 18 m.
The displacement is 18 meters.
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