The Mean deviation about Median for the given data. 52, 56, 66, 70, 75, 80, 82 is:
9
The data 52, 56, 66, 70, 75, 80, 82 has \(n=7\), so the median is the 4th term: \(M=70\).
Absolute deviations |xᵢ − 70|: 18, 14, 4, 0, 5, 10, 12.
Sum: \(18+14+4+0+5+10+12=63\).
\[\text{MD}_M = \frac{\sum|x_i-M|}{n}=\frac{63}{7}=\mathbf{9}\]
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