If the number of observations in a series is 15, then the third quartile is equal to:
12th observation in the series after arranging in ascending order
Understanding how to calculate quartiles is a fundamental concept in statistics. Quartiles divide a dataset into four equal parts. The first quartile (\(Q_1\)) represents the 25th percentile, the second quartile (\(Q_2\)) is the median (50th percentile), and the third quartile (\(Q_3\)) represents the 75th percentile.
To find the quartiles of a dataset, the first and most important step is to arrange the observations in ascending order.
For a dataset with \(n\) observations, the position of the quartiles can be found using specific formulas. The position of the third quartile (\(Q_3\)) is given by the formula:
\(\text{Position of } Q_3 = \frac{3(n+1)}{4}\)
In this question, the number of observations in the series is given as \(n = 15\). We need to find the third quartile.
Using the formula for the position of the third quartile (\(Q_3\)) with \(n=15\):
\(\text{Position of } Q_3 = \frac{3(15+1)}{4}\)
First, calculate the value inside the parentheses:
\(15+1 = 16\)
Now substitute this back into the formula:
\(\text{Position of } Q_3 = \frac{3 \times 16}{4}\)
Multiply 3 by 16:
\(3 \times 16 = 48\)
Finally, divide 48 by 4:
\(\text{Position of } Q_3 = \frac{48}{4} = 12\)
This result, 12, indicates that the third quartile (\(Q_3\)) is the 12th observation in the dataset.
It is crucial to remember that when calculating quartiles, the data must be arranged in ascending order. If the data is not ordered, calculating the position will not give the correct quartile value.
Let's look at the given options based on our calculation that the third quartile's position is the 12th observation:
Therefore, the third quartile is the 12th observation in the series after arranging the data in ascending order.
This method is commonly used for calculating quartiles when the number of observations is relatively small. If the position results in a fractional value, the quartile is usually found by interpolating between the two nearest observations.
| Concept | Description | Formula for Position (n observations) | Ordering Requirement |
|---|---|---|---|
| First Quartile (\(Q_1\)) | 25th Percentile | \(\frac{1(n+1)}{4}\) | Ascending Order |
| Second Quartile (\(Q_2\)) | Median (50th Percentile) | \(\frac{2(n+1)}{4}\) or \(\frac{(n+1)}{2}\) | Ascending Order |
| Third Quartile (\(Q_3\)) | 75th Percentile | \(\frac{3(n+1)}{4}\) | Ascending Order |
Different methods exist for calculating quartiles, particularly regarding how fractional positions are handled or alternative formulas for position. The formula \(\frac{k(n+1)}{4}\) for the \(k\)-th quartile's position is one common method, often called Method 1 or the exclusive method.
Another method (often called Method 3 or the inclusive method) uses the formula \(\frac{kn}{4}\) for the position of the \(k\)-th quartile within the *sorted* data indices (starting from 1), sometimes rounded up, or using interpolation based on \(\frac{kn}{100}\) for the \(k\)-th percentile. However, the \(\frac{k(n+1)}{4}\) method is straightforward and leads directly to the position within the ordered list as \(k=1, 2, 3\).
For \(n=15\) and using the \(\frac{k(n+1)}{4}\) method:
This calculation confirms the result for the third quartile.
If the mean deviation of a set of observations is 15, then the value of quartile deviation is:
The mean deviation from the average A is minimum if A represents
What is the mean deviation about the mean ?
What is the coefficient of mean deviation of 21, 34, 23, 39, 26, 37, 40, 20, 33, 27 (taken from mean)?
What is the mean deviation of first 10 even natural numbers?
The sum of deviations of n number of observations measured from 2.5 is 50. The sum of deviations of the same set of observations measured from 3.5 is -50. What is the value of n?