If the mean deviation of a set of observations is 15, then the value of quartile deviation is:
12.5
The question asks us to find the value of the quartile deviation given the mean deviation of a set of observations. While there isn't a single fixed mathematical formula that connects mean deviation and quartile deviation for all types of distributions, there is an empirical relationship that is often used, especially for distributions with moderate skewness, like the normal distribution.
For a normal distribution or distributions that are close to normal, there are approximate relationships between the standard deviation ($\sigma$), mean deviation (MD), and quartile deviation (QD).
The commonly used empirical relationships are:
Using these two relationships, we can derive an approximate relationship between mean deviation and quartile deviation.
From the first relationship, we have Standard Deviation $\approx \frac{5}{4} \times$ Mean Deviation.
Substituting this into the second relationship:
Quartile Deviation $\approx \frac{2}{3} \times \left(\frac{5}{4} \times \text{Mean Deviation}\right)$
Quartile Deviation $\approx \frac{10}{12} \times \text{Mean Deviation}$
Quartile Deviation $\approx \frac{5}{6} \times \text{Mean Deviation}
We are given that the mean deviation of the set of observations is 15.
Using the derived empirical relationship:
Quartile Deviation $\approx \frac{5}{6} \times \text{Mean Deviation}
Substitute the given value:
Quartile Deviation $\approx \frac{5}{6} \times 15
Quartile Deviation $\approx \frac{5 \times 15}{6}
Quartile Deviation $\approx \frac{75}{6}
Now, we calculate the value:
$\frac{75}{6} = \frac{25 \times 3}{2 \times 3} = \frac{25}{2} = 12.5$
So, the value of the quartile deviation is approximately 12.5 based on this empirical relationship.
| Given | Empirical Relationship | Calculation | Result |
|---|---|---|---|
| Mean Deviation = 15 | QD $\approx \frac{5}{6} \times$ MD | QD $\approx \frac{5}{6} \times 15 = 12.5$ | Quartile Deviation $\approx 12.5$ |
Based on the commonly used empirical relationship between mean deviation and quartile deviation, a mean deviation of 15 corresponds to a quartile deviation of approximately 12.5.
| Measure | Definition | Formula (Examples for ungrouped data) | Relationship (Empirical for Normal Distribution) |
|---|---|---|---|
| Quartile Deviation (QD) | Half the difference between the third and first quartiles. Also known as Semi-Interquartile Range. | $QD = \frac{Q_3 - Q_1}{2}$ | $QD \approx \frac{2}{3} \sigma$ |
| Mean Deviation (MD) | The average of the absolute deviations from the mean or median. | $MD = \frac{\sum |x_i - \bar{x}|}{n}$ (from mean) $MD = \frac{\sum |x_i - M|}{n}$ (from median) |
$MD \approx \frac{4}{5} \sigma$ |
| Standard Deviation ($\sigma$) | The square root of the variance, measuring the typical deviation from the mean. | $\sigma = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n}}$ or $\sqrt{\frac{\sum (x_i - \bar{x})^2}{n-1}}$ | $\sigma \approx \frac{3}{2} QD \approx \frac{5}{4} MD$ |
Measures of dispersion are statistical values that describe the spread or variability of data points in a distribution. Key measures include range, quartile deviation, mean deviation, variance, and standard deviation.
The empirical relationships discussed are approximations that hold best for symmetrical distributions like the normal distribution. For distributions that are highly skewed or have unusual shapes, these relationships may not be accurate.
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