The largest four-digit number which when divided by 6, 10 and 14 leaves remainder 3 in each case is:
9873
LCM of 6, 10 and 14: \(\text{LCM}(6,10,14) = 210\).
The required number is of the form \(210k+3\). For the largest 4-digit number: \(210k+3 \le 9999 \Rightarrow k \le 47.6\), so k=47.
\(210\times47+3 = 9870+3 = 9873\).
Hence, the largest four-digit number satisfying the condition is 9873.
The greatest three-digit number which is divisible by 14, 28, and 42 is:
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