All Exams Test series for 1 year @ ₹349 only
Question

The expenditure on the cost of living of a man and his family is 60% of his salary. He gets two increment of 30% and 60% in his salary. If his saving increases by 250% of his initial saving, then the new cost of living expenditure is what percentage (rounded off to the nearest integer) of the increased salary?

This question was previously asked in
SSC CGL 2022 Tier-II (Paper 2 JSO) Previous Year Paper (04-Mar-2023)
The correct answer is

32.7 Percent

Solving the Percentage Problem on Salary and Expenditure

The question asks us to find the new cost of living expenditure as a percentage of the new increased salary, given initial expenditure percentage, salary increments, and a percentage increase in savings.

Let's break down the problem step-by-step:

Step 1: Define Initial Conditions

Let the initial salary of the man be \(S\).

  • Initial expenditure on cost of living = \(60\%\) of initial salary.
  • Initial expenditure = \(0.60 \times S = 0.60S\).
  • Initial savings = Initial salary - Initial expenditure.
  • Initial savings = \(S - 0.60S = 0.40S\).

Step 2: Calculate the New Increased Salary

The man gets two increments in his salary: first \(30\%\), then \(60\%\) on the new salary after the first increment.

  • Salary after the first increment of \(30\%\):
    New salary \(S_1 = S + 30\%\) of \(S = S + 0.30S = 1.30S\).
  • Salary after the second increment of \(60\%\) on \(S_1\):
    New salary \(S_2 = S_1 + 60\%\) of \(S_1 = S_1 + 0.60S_1 = 1.60S_1\).
  • Substitute the value of \(S_1\):
    \(S_2 = 1.60 \times (1.30S)\).
  • Calculate the final increased salary:
    \(S_2 = (1.60 \times 1.30)S = 2.08S\).

The new increased salary is \(2.08S\).

Step 3: Calculate the New Savings

His saving increases by \(250\%\) of his initial saving.

  • Increase in saving = \(250\%\) of initial saving.
  • Increase in saving = \(\frac{250}{100} \times 0.40S = 2.5 \times 0.40S = 1.00S\).
  • New saving = Initial saving + Increase in saving.
  • New saving = \(0.40S + 1.00S = 1.40S\).

Step 4: Calculate the New Cost of Living Expenditure

The total salary is now divided between expenditure and savings. So, the new expenditure is the new salary minus the new savings.

  • New expenditure = New salary - New saving.
  • New expenditure = \(2.08S - 1.40S = 0.68S\).

Step 5: Calculate the New Expenditure as a Percentage of Increased Salary

We need to find what percentage the new cost of living expenditure (\(0.68S\)) is of the increased salary (\(2.08S\)).

Percentage = \(\left(\frac{\text{New expenditure}}{\text{Increased salary}}\right) \times 100\%\)

Percentage = \(\left(\frac{0.68S}{2.08S}\right) \times 100\%\)

The variable \(S\) cancels out:

Percentage = \(\left(\frac{0.68}{2.08}\right) \times 100\%\)

Percentage = \(\left(\frac{68}{208}\right) \times 100\%\)

Simplify the fraction \(\frac{68}{208}\):

  • Divide both by 4: \(\frac{68 \div 4}{208 \div 4} = \frac{17}{52}\).

Percentage = \(\left(\frac{17}{52}\right) \times 100\%\)

Now, perform the calculation:

\(\frac{17}{52} \times 100 \approx 0.326923 \times 100 \approx 32.6923\%\)

The question asks for the percentage rounded off to the nearest integer, but the options are given with one decimal place. Rounding \(32.6923\%\) to one decimal place gives \(32.7\%\).

Thus, the new cost of living expenditure is approximately \(32.7\%\) of the increased salary.

Revision Table: Summary of Calculations

Item Calculation/Value (in terms of initial salary S)
Initial Salary \(S\)
Initial Expenditure \(0.60S\)
Initial Savings \(0.40S\)
Increased Salary (New Salary) \(2.08S\)
Increase in Savings (250%) \(1.00S\)
New Savings \(1.40S\)
New Expenditure \(0.68S\)
New Expenditure as % of New Salary \(\left(\frac{0.68S}{2.08S}\right) \times 100\%\)
Final Percentage \(32.7\%\) (rounded to 1 decimal place)

Additional Information on Percentage Changes

Understanding consecutive percentage changes is important in such problems.

  • If a value increases by \(x\%\), the new value is the original value multiplied by \(\left(1 + \frac{x}{100}\right)\).
  • In this problem, the salary first increased by \(30\%\), so the multiplier was \(1 + \frac{30}{100} = 1.30\).
  • Then, it increased by \(60\%\), so the multiplier on the new value was \(1 + \frac{60}{100} = 1.60\).
  • The total multiplier for consecutive increases is the product of individual multipliers. Here, the total multiplier was \(1.30 \times 1.60 = 2.08\).
  • This means the final salary is \(2.08\) times the original salary, which is a \(108\%\) increase overall (\(2.08 - 1\) = \(1.08\), which is \(108\%\)).
  • An increase of \(250\%\) means the value becomes \(100\% + 250\% = 350\%\) of the original value, or \(3.5\) times the original value. In this case, the initial saving (\(0.40S\)) increased by \(250\%\), so the increase amount was \(2.50 \times 0.40S = 1.00S\). The new saving is the original plus the increase: \(0.40S + 1.00S = 1.40S\), which is indeed \(3.5 \times 0.40S\).

These concepts are fundamental when dealing with percentage-based financial problems.

Was this answer helpful?

Similar Questions

  1. The curved surface area and the volume of a cylindrical object are 88 cm 2and 132 cm 3, respectively. The height (in cm) of the cylindrical object is:

    (Take π =   \(\frac{{22}}{7}\) )

  2. The circumference of the base of a cylindrical vessel is 264 cm and its height is 50 cm. The capacity (in litres) of the vessel is:

    (Take π =  \(\frac{22}{7}\) )

  3. What will be the total cost (in Rs.) of polishing the curved surface of a wooden cylinder at rate of Rs. 50 per m 2, if its diameter is 70 cm and height is 6 m? (Take π =  \(\frac{22}{7}\) )

  4. A cylindrical tube, open at both ends, is made of a metal sheet which is 0.5 cm thick. Its outer radius is 4 cm and length is 2 m. How much metal (in cm 3) has been used in making the tube?

  5. The volume of a right circular cone is 308 cm 3 and the radius of its base is 7 cm. What is the curved surface area (in cm 2) of the cone? (Take π =  \(\frac{22}{7} \) )

  6. The slant height and radius of a right circular cone are in the ratio 29 ∶ 20. If its volume is 4838.4 π cm 3, then its radius is: 

  7. Six cubes, each of edge 2 cm, are joined end to end. What is the total surface area of the resulting cuboid in cm 2?

  8. Find the total surface area of a cube whose volume is 343 m3.

  9. A solid metallic sphere of radius 12 cm is melted and recast into a cone having diameter of the base as 12 cm. What is the height of the cone?

  10. A solid metallic cuboid of dimensions 12 cm × 54 cm × 72 cm is melted and converted into 8 cubes of the same size. What is the sum of the lateral surface areas (in cm 2) of 2 such cubes?


Important Questions from Solid Figures

  1. A cone and a hemisphere have equal bases and volumes. What is the ratio of the height of the cone to the radius of the hemisphere?

  2. A cube is 7 cm of an edge and another cube is 14 cm on an edge. The ratios of their surface areas are

  3. Using three distinct points which of the following shapes cannot be formed?

  4. Two cubes each of edge 12 cm are joined end to end. Find the surface area of the resulting cuboid.

  5. The areas of three adjacent faces of a cuboid are x, y, z. If the volume is V, then V 2will be equal to:

Need Expert Advice?
Upcoming Exams
SSC JE
November 02, 2026
SSC CPO
November 23, 2026
SSC CHSL
November 30, 2026
Test Series
SSC CGL img
SSC
SSC CGL (Tier I + Tier II) 2026 Mock Test Series - Latest Pattern
2509 Tests 6 Tests Free
8792 Attempts
4.2(941)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App