The diagonals of a rhombus-shaped field are 224 m and 420 m long. What is the perimeter (in m) of the field?
952
The diagonals of a rhombus bisect each other at right angles, so each side is the hypotenuse of a right triangle formed by the half-diagonals.
Half-diagonals: \(\frac{224}{2} = 112\) m and \(\frac{420}{2} = 210\) m.
Side \(= \sqrt{112^2 + 210^2} = \sqrt{12544 + 44100} = \sqrt{56644} = 238\) m.
Perimeter \(= 4 \times \text{side} = 4 \times 238 = 952\) m.
Hence, the perimeter of the field is 952 m.
The shorter side of a rectangle is 15 cm less than the longer side. The numerical value of its area is equal to 5 times the numerical value of its perimeter. What is the length (in cm) of its longer side?