The current age of Savan is four times the age of Akshan. 10 years from now, Savan’s age will be twice the age of Akshan. What is Savan’s current age?
20 years
This problem involves the ages of two people, Savan and Akshan, at two different points in time: currently and 10 years from now. We are given two relationships between their ages at these times and need to find Savan's current age.
To solve this type of age problem, we can use variables to represent the unknown ages and translate the given information into algebraic equations.
Now, let's express the given relationships as equations:
We now have a system of two linear equations with two variables:
Equation 1: \(S = 4A\)
Equation 2: \(S + 10 = 2(A + 10)\)
We can use the substitution method to solve this system. Substitute the expression for \(S\) from Equation 1 into Equation 2:
Replace \(S\) with \(4A\) in Equation 2:
\(4A + 10 = 2(A + 10)\)
Now, solve for \(A\):
So, Akshan's current age is 5 years.
Now that we have Akshan's current age (\(A=5\)), we can find Savan's current age (\(S\)) using Equation 1:
\(S = 4A\)
\(S = 4 \times 5\)
\(S = 20\)
Thus, Savan's current age is 20 years.
Let's check if these ages satisfy the conditions given in the problem:
Both conditions are satisfied, confirming our solution is correct.
Savan’s current age is 20 years.
| Concept | Explanation | Application in Problem |
|---|---|---|
| Variables | Symbols (like letters) used to represent unknown quantities. | Using \(S\) for Savan's age and \(A\) for Akshan's age. |
| Translating Words to Equations | Converting statements about relationships into mathematical equations. | "four times" becomes multiplication (\(4A\)), "will be" becomes equality (\(=\)). |
| Linear Equations | Equations where variables have a power of 1. | \(S = 4A\) and \(S + 10 = 2(A + 10)\) are linear equations. |
| System of Equations | A set of two or more equations with the same variables. | We had two equations involving \(S\) and \(A\). |
| Substitution Method | Solving one equation for a variable and plugging that into the other equation. | Substituting \(S = 4A\) into the second equation. |
| Solving for Variables | Isolating a variable to find its value using algebraic operations. | Using inverse operations (addition/subtraction, multiplication/division) to find \(A\) and then \(S\). |
| Verification | Plugging the found values back into the original problem statements to check if they are true. | Checking if \(20 = 4 \times 5\) and \(30 = 2 \times 15\). |
Age word problems are common in algebra. They often involve relationships between people's ages at different points in time (past, present, future). Here are some tips for solving them:
Practice with different variations of age problems will help you become more comfortable setting up and solving the equations.
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