Rs. 820 is divided among 6 men, 8 women, and 12 boys in such a way that every woman gets an amount equal to that received by one man and one boy combined and that every man gets one and a half times the amount received by a boy. What is the total amount received by 8 women?
Rs. 400
The problem describes how a total amount of Rs. 820 is divided among a group of men, women, and boys. We are given specific relationships between the amounts received by individuals from each group. Our goal is to find the total amount received by all the women.
Let's represent the amount received by one person from each group:
Based on the problem statement, we can write down the relationships:
Now we have a system of three equations with three variables (\(M\), \(W\), \(B\)). We can use substitution to solve for the individual amounts.
Substitute Equation 3 (\(M = \frac{3}{2} B\)) into Equation 2 (\(W = M + B\)):
\(W = \frac{3}{2} B + B\)
To add the terms on the right side, find a common denominator:
\(W = \frac{3}{2} B + \frac{2}{2} B\)
\(W = \frac{3B + 2B}{2}\)
\(W = \frac{5}{2} B\) (Equation 4)
Now we have expressions for \(M\) (Equation 3) and \(W\) (Equation 4) in terms of \(B\). Substitute these expressions into Equation 1 (\(6M + 8W + 12B = 820\)):
\(6 \left(\frac{3}{2} B\right) + 8 \left(\frac{5}{2} B\right) + 12B = 820\)
Simplify the terms:
\(\left(\frac{6 \times 3}{2}\right) B + \left(\frac{8 \times 5}{2}\right) B + 12B = 820\)
\(\left(\frac{18}{2}\right) B + \left(\frac{40}{2}\right) B + 12B = 820\)
\(9B + 20B + 12B = 820\)
Combine the terms involving \(B\):
\((9 + 20 + 12) B = 820\)
\(41B = 820\)
Now, solve for \(B\):
\(B = \frac{820}{41}\)
\(B = 20\)
So, the amount received by one boy is Rs. 20.
Now that we know the value of \(B\), we can find the values of \(M\) and \(W\) using the relationships we found:
Let's check if these individual amounts add up to the total amount of Rs. 820:
Total distributed amount = \(180 + 400 + 240 = 820\).
This matches the given total amount, confirming our calculations for individual shares are correct.
The question asks for the total amount received by 8 women. Since each woman receives Rs. 50, the total amount for 8 women is:
Total amount for 8 women = \(8 \times W = 8 \times 50 = 400\)
The total amount received by 8 women is Rs. 400.
| Group | Number | Amount per person | Total Amount for Group |
|---|---|---|---|
| Men | 6 | Rs. 30 | \(6 \times 30 = 180\) |
| Women | 8 | Rs. 50 | \(8 \times 50 = 400\) |
| Boys | 12 | Rs. 20 | \(12 \times 20 = 240\) |
| Grand Total | \(180 + 400 + 240 = 820\) | ||
By setting up equations based on the given information and solving them, we found the amount received by each boy, man, and woman. The total amount received by 8 women is Rs. 400.
| Concept | Explanation | Application in Problem |
|---|---|---|
| Setting up Variables | Using symbols (like \(B\), \(M\), \(W\)) to represent unknown quantities. | Representing the amount each boy, man, and woman receives. |
| Formulating Equations | Translating word problems into mathematical equations based on relationships between quantities. | Writing equations for the total amount, woman's share, and man's share. |
| Substitution Method | Solving a system of equations by expressing one variable in terms of another and substituting into other equations. | Used to find the value of \(B\) by expressing \(M\) and \(W\) in terms of \(B\). |
| Solving Linear Equations | Finding the value of the unknown variable that satisfies the equation. | Used to find the specific amounts \(B\), \(M\), and \(W\). |
| Verification | Checking if the calculated values satisfy the original conditions of the problem. | Summing up the total amounts for each group to ensure it equals Rs. 820. |
This problem is an example of a proportional distribution question. These problems involve dividing a total quantity among different categories based on given ratios or relationships between the categories. The key steps usually involve:
Understanding how to set up and solve systems of linear equations is crucial for these types of problems. Sometimes, the relationships are given directly as ratios (e.g., man:boy ratio is 3:2), which can also be used to set up the equations.
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