Calculating Cost of More Pencils and Pens
We are given the cost of a specific number of pencils and pens.
- Cost of 10 pencils and 12 pens = ₹150.
We need to find the cost of 30 pencils and 36 pens.
Cost Relationship Analysis
Let $P$ be the cost of one pencil and $N$ be the cost of one pen.
From the given information, we can write the equation:
$10P + 12N = 150$
We need to calculate the cost for 30 pencils and 36 pens, which can be represented as:
$30P + 36N$
Notice that the number of pencils and pens required is exactly 3 times the number given:
- $30 = 3 \times 10$
- $36 = 3 \times 12$
Therefore, the expression for the required cost can be rewritten as:
$30P + 36N = (3 \times 10)P + (3 \times 12)N$
Factor out the common multiplier, 3:
$30P + 36N = 3 \times (10P + 12N)$
Final Cost Calculation
Substitute the given cost ($10P + 12N = 150$) into the equation:
$30P + 36N = 3 \times 150$
Calculate the final cost:
$3 \times 150 = 450$
So, the cost of 30 pencils and 36 pens is ₹450.
Similar Questions
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Important Questions from Linear Equation in 2 Variable
What is the solution of the following equations ?
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If 8k 6+ 15k 3– 2 = 0, then the positive value of \(\left( {{\rm{k}}\,{\rm{ + }}\,\frac{1}{{\rm{k}}}} \right)\) is :
