If \(1.2x = 0.5y\), find the value of \(\dfrac{x+y}{x-y}\).
\(-\tfrac{17}{7}\)
\(1.2x = 0.5y\) gives \(y = 2.4x\).
Substituting into the required expression: \(\dfrac{x+y}{x-y} = \dfrac{x+2.4x}{x-2.4x} = \dfrac{3.4x}{-1.4x} = -\dfrac{17}{7}\).
Hence, the value of \(\dfrac{x+y}{x-y}\) is \(-\tfrac{17}{7}\).
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