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Question

Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77, but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A?

The correct answer is

Rs. 13. Rs. 17

Calculating Bus Ticket Fares: City A to B and C

This problem involves finding the cost of bus tickets between different cities based on given purchase scenarios. We can solve this using a system of linear equations.

Defining Variables for Fares

Let's define the unknown fares:

  • Let the fare for a bus ticket from city A to city B be '$x$' (in Rs.).
  • Let the fare for a bus ticket from city A to city C be '$y$' (in Rs.).

Formulating Equations from Given Information

We are given two conditions:

  1. Two tickets from city A to B and three tickets from city A to C cost Rs. 77. This can be written as the equation:

    $2x + 3y = 77$ (Equation 1)

  2. Three tickets from city A to B and two tickets from city A to C cost Rs. 73. This can be written as the equation:

    $3x + 2y = 73$ (Equation 2)

Solving the System of Linear Equations

We need to solve these two equations simultaneously to find the values of $x$ and $y$. We can use the elimination method.

Step 1: Multiply Equations to Match Coefficients

To eliminate one variable, we can multiply the equations by suitable numbers. Let's multiply Equation 1 by 3 and Equation 2 by 2, so the coefficients of '$x$' become the same.

Multiplying Equation 1 by 3:

$3 \times (2x + 3y) = 3 \times 77$
$6x + 9y = 231$ (Equation 3)

Multiplying Equation 2 by 2:

$2 \times (3x + 2y) = 2 \times 73$
$6x + 4y = 146$ (Equation 4)

Step 2: Eliminate One Variable

Now, subtract Equation 4 from Equation 3 to eliminate '$x$':

$(6x + 9y) - (6x + 4y) = 231 - 146$
$6x + 9y - 6x - 4y = 85$
$5y = 85$

Now, solve for '$y$':

$y = \frac{85}{5}$
$y = 17$

Step 3: Substitute to Find the Other Variable

Substitute the value of '$y$' (which is 17) back into either Equation 1 or Equation 2 to find '$x$'. Let's use Equation 1:

$2x + 3y = 77$
$2x + 3(17) = 77$
$2x + 51 = 77$

Now, solve for '$x$':

$2x = 77 - 51$
$2x = 26$
$x = \frac{26}{2}$
$x = 13$

Final Fares

So, the fare for a bus ticket from city A to B is Rs. 13, and the fare from city A to C is Rs. 17.

The fares for cities B and C from A are Rs. 13 and Rs. 17, respectively.

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Important Questions from Linear Equation in 2 Variable

  1. If 2 x + 3 y = 17;

    2 x+2  - 3 y+1  = 5

    then the values of x and y are:

  2. The solution of pair of linear equations \(\dfrac{1}{2}x+\dfrac{2}{3}y=-1,x-\dfrac{1}{3}y=3\) by the elimination method, is:

  3. Kumar tried his skill at shooting at a fun fair. He has to hit the target and if he hits the target he gets 1 Rs. and if he misses he has to pay 50 paise. He attempted 25 shots and won 10 Rs. In how many did he hit the target?

  4. The sum of two numbers is 66 and their difference is 22. What is the ratio of the two numbers?

  5. Shyam spent half of his money and was left with as many as he had rupees before, but with half as many rupees as he had paise before. Which of the following is a possible amount of money he is left with?

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