Sum of twice a fraction and its reciprocal is 17/6. What is the fraction?
3/4
Let the fraction be \(x\). Then:
\[2x+\frac{1}{x}=\frac{17}{6}\]
Multiply through by \(6x\):
\[12x^2-17x+6=0\]
Factor:
\[(3x-2)(4x-3)=0\implies x=\tfrac{2}{3}\text{ or }\tfrac{3}{4}\]
Among the options, only \(\dfrac{3}{4}\) appears. Check: \(2\cdot\tfrac{3}{4}+\tfrac{4}{3}=\tfrac{3}{2}+\tfrac{4}{3}=\tfrac{9+8}{6}=\tfrac{17}{6}\).
Therefore the fraction is \(\dfrac{3}{4}\).
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