Number of real roots of the quadratic equation 3x 2+ 4x + 25 = 0 is
nil
To determine the number of real roots of a quadratic equation, we use the discriminant. A quadratic equation is typically written in the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are real numbers and \(a \neq 0\).
The discriminant, denoted by the symbol \(\Delta\) (or \(D\)), is a crucial part of the quadratic formula. It helps us understand the nature of the roots without actually solving the equation. The formula for the discriminant is:
\[ \Delta = b^2 - 4ac \]
Based on the value of the discriminant, we can determine the number and type of roots:
Let's identify the coefficients \(a\), \(b\), and \(c\) from the given quadratic equation: \(3x^2 + 4x + 25 = 0\).
Now, we will substitute these values into the discriminant formula:
\[ \Delta = b^2 - 4ac \]
\[ \Delta = (4)^2 - 4(3)(25) \]
\[ \Delta = 16 - 12(25) \]
\[ \Delta = 16 - 300 \]
\[ \Delta = -284 \]
Our calculated discriminant is \(\Delta = -284\).
Since \(\Delta = -284\), which is less than zero (\(\Delta < 0\)), the quadratic equation \(3x^2 + 4x + 25 = 0\) has no real roots.
This means there are "nil" real roots for the given quadratic equation. The roots, in this case, would be complex numbers.
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