If (x – 2) and (x + 3) are the factors of the equation x 2+ k 1x + k 2= 0, then what are the values of k 1 and k 2?
k1 = 1, k2 = -6
If \((x-2)\) and \((x+3)\) are factors of the monic quadratic, then
\[(x-2)(x+3)=x^2+x-6\]
Comparing with \(x^2+k_1 x+k_2=0\): \(k_1=1\) and \(k_2=-6\).
Therefore \(k_1=1,\ k_2=-6\).
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