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Question

If one of the roots of the equation $x^2 - 19x + 88 = 0$ is 8, then what is the other root?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
11

Quadratic Equation Root Calculation

This solution finds the second root of the quadratic equation $x^2 - 19x + 88 = 0$, given that one root is 8.

Equation and Known Root

The provided quadratic equation is:

$x^2 - 19x + 88 = 0$

We are given that one root, let's call it $\alpha$, is 8.

Finding the Other Root Using Sum of Roots

In a quadratic equation $ax^2 + bx + c = 0$, the sum of the roots ($\alpha + \beta$) is given by the formula $-b/a$.

  • For the equation $x^2 - 19x + 88 = 0$, we have $a=1$, $b=-19$, and $c=88$.
  • The sum of the roots is $\alpha + \beta = -(-19)/1 = 19$.
  • Since we know $\alpha = 8$, we can substitute it into the sum: $8 + \beta = 19$.
  • Solving for $\beta$, we get: $\beta = 19 - 8 = 11$.

Alternative Method: Product of Roots

The product of the roots ($\alpha \beta$) for the equation $ax^2 + bx + c = 0$ is given by $c/a$.

  • The product of the roots is $\alpha \beta = 88/1 = 88$.
  • Substituting the known root $\alpha = 8$: $8 \beta = 88$.
  • Solving for $\beta$: $\beta = 88 / 8 = 11$.

Result

Both methods show that the other root ($\beta$) of the equation $x^2 - 19x + 88 = 0$ is 11.

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Important Questions from Quadratic Equation

  1. If 2x 2+ 5x + 1 = 0, then one of the values of \(x - \frac{1}{{2x}}\)  is:

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  4. If \(\sqrt{x}{}-{1\over\sqrt{x}}=\sqrt5\) \(x \ne 0\) , then what is the value of  \((x^4+{1\over{x^2}})\over(x^2+1) \)  ?

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