This solution finds the second root of the quadratic equation $x^2 - 19x + 88 = 0$, given that one root is 8.
The provided quadratic equation is:
$x^2 - 19x + 88 = 0$
We are given that one root, let's call it $\alpha$, is 8.
In a quadratic equation $ax^2 + bx + c = 0$, the sum of the roots ($\alpha + \beta$) is given by the formula $-b/a$.
The product of the roots ($\alpha \beta$) for the equation $ax^2 + bx + c = 0$ is given by $c/a$.
Both methods show that the other root ($\beta$) of the equation $x^2 - 19x + 88 = 0$ is 11.
The positive value of m for which the roots of the equation ${12}{x}^2 + mx + 6 = 0$ are in the ratio of 2 : 3 is ______.
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