The magnetic property of an ion depends on the presence of unpaired electrons. We need to determine the electronic configuration of the peroxide ion ($O_2^{2-}$) using Molecular Orbital (MO) theory.
The peroxide ion has the formula $O_2^{2-}$. Each oxygen atom has 8 electrons. Therefore, the total number of electrons in the peroxide ion is:
Total electrons = (2 $\times$ 8) + 2 = 18 electrons.
The molecular orbital configuration for a molecule or ion with 18 electrons (like $O_2^{2-}$) is typically:
$(\sigma_{1s})^2 (\sigma_{1s}^*)^2 (\sigma_{2s})^2 (\sigma_{2s}^*)^2 (\sigma_{2p})^2 (\pi_{2p})^4 (\pi_{2p}^*)^4$
Let's check the total electrons filled:
All 18 electrons are accommodated in the molecular orbitals, and importantly, all orbitals are completely filled, meaning all electrons are paired.
Since the peroxide ion ($O_2^{2-}$) has all its electrons paired according to its MO configuration, it exhibits diamagnetic behavior.
The calculated magnetic moment for low spin $[Ru(EDTA)]^-$ is
Nickel combines with a uninegative monodentate ligand (X−) to form a paramagnetic complex [NiX4]2−. The hybridisation involved and number of unpaired electrons present in the complex are respectively
Which of the following statements is incorrect ?
The crystal field splitting energy of $[\text{Co(oxalate)}_3]^{3-}$ complex is '$n$' times that of the $[\text{Cr(oxalate)}_3]^{3-}$ complex. Here '$n$' is ___________. (Assume $\Delta_o >> P$)