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For the metal complex $[Co(NH_3)_5SO_4]Br$, coordination number, oxidation number, number of d-electrons and number of unpaired d-electrons are respectively

This question was previously asked in
WBJEE 2026 Physics and Chemistry Question Paper (24-May-2026)
The correct answer is
6, 3, 6, 0

To solve the given question, we need to analyze the coordination complex \([Co(NH_3)_5SO_4]Br\). Let's go through each part step-by-step:

  1. **Coordination Number**: The coordination number is determined by the number of ligand atoms that are directly bonded to the central metal ion. In \([Co(NH_3)_5SO_4]Br\), we have:
    • \(5\) ammonia molecules \((NH_3)\) each coordinating through a nitrogen atom.
    • \((SO_4)^{2-}\) acts as a monodentate ligand here since it's written within the complex ion brackets.
  2. **Oxidation Number**: Let the oxidation state of Co be \(x\).

Considering electroneutrality, the complex is neutral:

  1. \(x + 5(0) + (-2) + (+1) = 0\) (since NH3 has no charge and Br- is outside the complex)

This simplifies to:

  1. \(x - 2 + 1 = 0\)

Therefore, \(x = +3\).

  1. **Number of d-Electrons**: The electronic configuration of \(Co\) in an isolated state is \([Ar] 3d^7 4s^2\). In the oxidation state of \(+3\), cobalt would lose three electrons, which results in a configuration of \(3d^6\) for the Co3+ ion.
  2. **Number of Unpaired d-Electrons**: With a \(3d^6\) configuration and being in a low-spin state due to strong field ligands like NH3, all electrons are paired.
    • Therefore, the number of unpaired d-electrons is \(0\).

By analyzing all these factors, the characteristics are: Coordination number = \(6\), Oxidation number = \(+3\), Number of d-electrons = \(6\), and Number of unpaired d-electrons = \(0\).

Hence, the correct answer is 6, 3, 6, 0.

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Important Questions from Inorganic Chemistry

  1. A chromium complex with a formula $\text{CrCl}_3\cdot 6\text{H}_2\text{O}$ has a spin only magnetic moment value of $3.87 \text{ BM}$ and its solution conductivity corresponds to $1 : 2$ electrolyte. $2.75 \text{ g}$ of the complex solution was initially passed through a cation exchanger. The solution obtained after the process was reacted with excess of $\text{AgNO}_3$. The amount of $\text{AgCl}$ formed in the above process is _____ g. (Nearest integer)
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  2. Consider the following reactions :
    $\text{NaCl} + \text{K}_2\text{Cr}_2\text{O}_7 + \text{H}_2\text{SO}_4 \rightarrow \text{A} + \text{KHSO}_4 + \text{NaHSO}_4 + \text{H}_2\text{O}$
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  5. Which of the following is the structure of pyrosulphuric acid?
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