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Question

Which of the following statements is incorrect ?

The correct answer is

[CoF6]3− is paramagnetic with 2 unpaired electrons.

The number of unpaired electrons in a complex follows from the d-electron count of the metal ion and, for d4–d7 octahedral ions, from whether the ligand forces spin pairing (strong field) or not (weak field).

Step 1 — [VF6]3−: V3+ is 3d2; the two electrons occupy separate t2g orbitals, so it is paramagnetic with 2 unpaired electrons. True.

Step 2 — [CuCl4]2−: Cu2+ is 3d9, which always has 1 unpaired electron. True.

Step 3 — [Co(NH3)6]3+: Co3+ is 3d6; NH3 causes pairing, giving low-spin t2g6 with no unpaired electron, so the ion is diamagnetic. True.

Step 4 — [CoF6]3−: Co3+ is 3d6, but F− is a weak-field ligand, so the ion is high spin, t2g4eg2, with 4 unpaired electrons (\(\mu=\sqrt{4\times6}=\sqrt{24}\approx4.90\ \text{BM}\)). The claim of 2 unpaired electrons is false.

[CoF6]3− is paramagnetic with 2 unpaired electrons. option is correct.

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Important Questions from Inorganic Chemistry

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