Which of the following statements is incorrect ?
[CoF6]3− is paramagnetic with 2 unpaired electrons.
The number of unpaired electrons in a complex follows from the d-electron count of the metal ion and, for d4–d7 octahedral ions, from whether the ligand forces spin pairing (strong field) or not (weak field).
Step 1 — [VF6]3−: V3+ is 3d2; the two electrons occupy separate t2g orbitals, so it is paramagnetic with 2 unpaired electrons. True.
Step 2 — [CuCl4]2−: Cu2+ is 3d9, which always has 1 unpaired electron. True.
Step 3 — [Co(NH3)6]3+: Co3+ is 3d6; NH3 causes pairing, giving low-spin t2g6 with no unpaired electron, so the ion is diamagnetic. True.
Step 4 — [CoF6]3−: Co3+ is 3d6, but F− is a weak-field ligand, so the ion is high spin, t2g4eg2, with 4 unpaired electrons (\(\mu=\sqrt{4\times6}=\sqrt{24}\approx4.90\ \text{BM}\)). The claim of 2 unpaired electrons is false.
[CoF6]3− is paramagnetic with 2 unpaired electrons. option is correct.
The calculated magnetic moment for low spin $[Ru(EDTA)]^-$ is
Nickel combines with a uninegative monodentate ligand (X−) to form a paramagnetic complex [NiX4]2−. The hybridisation involved and number of unpaired electrons present in the complex are respectively
The crystal field splitting energy of $[\text{Co(oxalate)}_3]^{3-}$ complex is '$n$' times that of the $[\text{Cr(oxalate)}_3]^{3-}$ complex. Here '$n$' is ___________. (Assume $\Delta_o >> P$)